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viktelen [127]
3 years ago
14

Can somebody please help me ?

Chemistry
1 answer:
larisa [96]3 years ago
4 0

Answer:

I belive it is either a element or co mpound Hope this helped :D :3

Explanation:

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A sample of silicon has an average atomic mass of 28.084amu. In the sample, there are three isotopic forms of silicon. About 92.
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A sample of silicon has an average atomic mass of 28.084amu. In the sample, there are three isotopic forms of silicon. About 92.22% of silicon atoms are 27.9769amu, which have the mass of 28Si; about 4.68% are 28.9764amu, which have the mass of 29Si, and the isotope 30Si, makes up the remaining 3.10%. Calculate the atomic mass of 30Si. Report your answer with three significant figures <u>The percentage abundance for  </u><u>isotope </u><u>is 3.09 %.</u>

<h3>What is isotopes?</h3>

Isotopes are two or more atom types that share the same atomic number (number of protons in their nuclei), location in the periodic table, and chemical element but have distinct nucleon numbers (mass numbers) as a result of having a different number of neutrons in their nuclei. Although the chemical properties of each isotope of a given element are nearly identical, they differ in their atomic weights and physical characteristics.

The word "isotope" is derived from the Greek words "isos" and "topos," both of which imply "the same location." As a result, the name refers to the fact that various isotopes of a given element occupy the same spot on the periodic table. Scottish physician and author Margaret Todd first used it in a recommendation in 1913.

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brainly.com/question/364529

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2 years ago
Convert 614 Cal to J. Only include the numerical value in your answer. Respond with the correct number of significant figures in
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Answer:

Explanation:

Given parameters:

Number of given calories = 614 cal

Note that  1cal = 4.18J

Now to convert the given calories to joule, we use the relationship below:

         Since 1Cal gives 4.18Joule of energy

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This written as 2.57 x 10³J because it has three significant numbers of 2, 5 and 7.

In writing an operation that involves deducing the significant numbers, we simply express our answer to that shows the lowest number of significant numbers. Our problem has 3 significant numbers each and the answer is given in that regard.

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