Answer:
4.35 atm
Explanation:
According to the information given;
- Initial volume of the gas, V₁ is 2.50 L
- Initial pressure of the gas is standard pressure P₁, normally 1 atm
- New volume of the gas, V₂ is 575 mL
We are required to determine the new pressure of the gas, P₂ ;
To answer the question, we are going to use the Boyle's law, that relates pressure and volume at constant temperature.
According to Boyle's law;
P₁V₁ = P₂V₂
Therefore, to determine the new pressure, P₂, we rearrange the formula;
New pressure, P₂ = P₁V₁ ÷ V₂
Thus;
P₂ = ( 1 atm × 2.50 L) ÷ 0.575 L
= 4.3478 atm
= 4.35 atm
Therefore, the new pressure of the gas is 4.35 atm
<span>amount of heat and energy(energy of fusion)</span>
I am sorry bro I don't know
<h3>
Answer:</h3>
4.73 × 10^4 m
<h3>
Explanation:</h3>
From the question;
Frequency of the photon = 634 × 10^12 Hz
We are required to calculate the wavelength of the photon.
We need to know the relationship between wavelength and frequency of a wave.
The relationship between f and λ is given by;
c = fλ
Where c, is the speed of light, 2.998 × 10^8 m/s
Therefore, to get the wavelength we rearrange the formula such that;
λ = c ÷ f
= 2.998 × 10^8 m/s ÷ 634 × 10^12 Hz
= 4.73 × 10^-5 m
But we require wavelength in nm
1 M = 10^9 nm
Therefore;
Wavelength = 4.73 × 10^-5 m × 10^9 nm/m
= 4.73 × 10^4 m
Hence, the photon's wavelength is 4.73 × 10^4 m
The answer is 14.22 mg / (mm^2)
