The molarity of the resulting solution obtained by diluting the stock solution is 3 M
<h3>Data obtained from the question </h3>
- Molarity of stock solution (M₁) = 15 M
- Volume of stock solution (V₁) = 500 mL
- Volume of diluted solution (V₂) = 2.5 L = 2.5 × 1000 = 2500 mL
- Molarity of diluted solution (M₂) =?
<h3>How to determine the molarity of diluted solution </h3>
M₁V₁ = M₂V₂
15 × 500 = M₂ × 2500
7500 = M₂ × 2500
Divide both side by 2500
M₂ = 7500 / 2500
M₂ = 3 M
Thus, the volume of the resulting solution is 3 M
Learn more about dilution:
brainly.com/question/15022582
#SPJ1
Amphiprotic compounds are able to both donate and accept a proton.
Amphiprotic compounds contain a hydrogen atom and lone pair of valence electron.
For example, HSO₃⁻ (hydrogen sulfate ion) is an amphiprotic compound.
Balanced chemical equation for reaction when HSO₃⁻ donate protons to water:
HSO₃⁻(aq) + H₂O(l) ⇄ SO₄²⁻(aq) + H₃O⁺(aq).
Ka = [SO₄²⁻] · [H₃O⁺] / [HSO₃⁻]
Balanced chemical equation for reaction when HSO₃⁻ accepts protons from water:
HSO₃⁻(aq) + H₂O(l) ⇄ H₂SO₄(aq) + OH⁻(aq).
Kb = [H₂SO₄] · [OH⁻] / [HSO₃⁻]
Water (H₂O), amino acids, hydrogen carbonate ions (HCO₃⁻) are examples of amphiprotic species.
Another example, water is an amphiprotic substance:
H₂O + HCl → H₃O⁺ + Cl⁻
H₂O + NH₃ → NH₄⁺ + OH⁻
More about amphiprotic compounds: brainly.com/question/3421406
#SPJ4
Answer:
About 25 kPa
Explanation:
Pressure decreases with height above sea level.
The calculation is rather complicated, so I will refer to the figure below.
It shows that the pressure at 10 km is about 25 kPa.
The best and most correct answer among the choices provided by your question is the second choice or letter B.
The list the elements in order of increasing malleability would be: <span>Se, Sb, Sn.
</span><span>
Since, Se = nonmetal, Sb = metalloid, Sn= metal </span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
Answer:
las rondas sirven para ayudar con problemas matematicos asi como cilindros
