What is the value of a conversion factor ratio?<br>A.1<br>B.3<br>C.10<br>D.12

Why are some areas in Europe seeing a partial solar eclipse while others are observing a total solar eclipse?

GuDViN [60]

Answer:

Objects between the source and observer produce possible shadows known as the umbra and the penumbra.

The umbra is a totally shadowed area, no light travels directly from the source to the observer.

The penumbra is a partially shadowed are where some of the source light travels directly to the observer an some of the source light is blocked from the observer (the object blocking the light is not a point object).

The question apparently refers to the differences seen by the observers.

5 0

3 years ago

macmillan learning im Hamm at big bend Coty Conege A 1.30-m-long rope is stretched between two points with a tension that makes

san4es73 [151]

Answer:

0.87 m

70.6 Hz

Explanation:

$L$ = length of the rope = 1.30 m

$n$ = order of the harmonic = 3

$\lambda$ = Wavelength

Wavelength is given as

$\lambda = \frac{2L}{n}$

$\lambda = \frac{2(1.30)}{3}$

$\lambda$ = 0.87 m

$v$ = Speed of transverse wave = 61.4 m/s

$f$ = frequency of the third harmonic

frequency is given as

$f = \frac{v}{\lambda }$

$f = \frac{61.4}{0.87}$

$f$ = 70.6 Hz

5 0

3 years ago

A coil has an inductance of 6.00 mH, and the current in it changes from 0.200 A to 1.50 A in a time interval of 0.300 s. Find th

Andre45 [30]

Answer:

0.026 V

Explanation:

Given that,

Inductance of the coil, L = 6 mH

The current changes from 0.2 A to 1.5 A in a time interval of 0.3 s

We need to find the magnitude of the average induced emf in the coil during this time interval. The formula for the induced emf is given by :

$\epsilon=L\dfrac{dI}{dt}\\\\=6\times 10^{-3}\times \dfrac{1.5-0.2}{0.3}\\\\=0.026\ V$

So, the magnitude of induced emf is 0.026 volts.

5 0

3 years ago

A 12.0 V car battery is being used to power the headlights of a car. Each of the two headlights has a power rating of 37.7 Watts

marshall27 [118]

Answer:

3.921*10^19 electrons

Explanation:

To find the number of electron that trough the car battery you first calculate the current by using the following formula, which relates the power with the voltage:

$P=IV$ (1)