Answer:
We have the next relation:
A = (b*d)/c
because we have direct variation with b and d, but inversely variation with c.
Now, if we have 3d instead of d, we have:
A' = (b*(3d))/c
now, we want A' = A. If b,c, and d are the same in both equations, we have that:
3bd/c = b*d/c
this will only be true if b or/and d are equal to 0.
If d remains unchanged, and we can play with the other two variables we have:
3b'd/c' = bd/c
3b'/c' = b/c
from this we can took that: if c' = c, then b' = b/3, and if b = b', then c' = 3c.
Of course, there are other infinitely large possible combinations that are also a solution for this problem where neither b' = b or c' = c
For the first one it is 5 x10^{8}
and for the second one it is 0.0005 = 5 × 0.0001 = 5 × 10−4
Answer:
m = -4
Step-by-step explanation:
- 36 - m = 8(4+2m)
- 36 - m = 32+16m (to remove m from the left side, we need to add m to both sides)
- 36 = 32+17m (subtract 32 from both sides)
- 68 = 17m (divide by 17 on both sides)
-4 = m
Answer:
A.) -84
B.) -6
Step-by-step explanation:
I hope I helped! ^-^
