Which statements are true about

Use two points to enter an equation for the function. Give your answer in the form a(b)^n. In the event that a = 1, give your an

levacccp [35]

Answer:

$m(n) = 24 (0.75)^n$

Step-by-step explanation:

1) The two points are:

a) On the first swing she swings forward by 18 degrees: (1, 18)

b) On the second swing she only comes 13.5 degrees forward: (2,13.5)

2) The general equation using the form given is:

$m(n)=A(B)^n$

3) Substitute the two points:

$18=A(B)\\ \\ 13.5=A(B)^2$

4) Divide the second equation by the first one:

⇒ 13.5 / 18 = B

⇒ B = 0.75

5) Substitue B = 0.75 into the first equation:

18 = A (0.75) ⇒ A = 18 / 0.75 = 24

Hence, the equation is:

$m(n) = 24 (0.75)^n$

5 0

3 years ago

Write a letter to the congressman telling him why it is important to find new sources of energy.

bekas [8.4K]

The importance of finding new sources of energy,Are we are running out of resources on our planet. There are so many resources that are reusable. an ones that only have a certain amount of an we are running out of it. so if we find new sources of energy we could save our planet it an stop it from wasting an killing out planet

7 0

3 years ago

Read 2 more answers

How does 4go into 20

kow [346]

Answer:

It goes into 20 because 4 is a factor of 20 on the multiplication chart

Step-by-step explanation:

4*1=4

4*2=8

4*3=12

4*4=16

4*5=20

4+4+4+4+4

8+8+4

16+4

20

4 0

3 years ago

Read 2 more answers

Help me if you can please

Luden [163]

Answer:

the question is not visible

8 0

2 years ago

A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3>Solution:</h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

The area of rectangle is given as:

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

General form of quadratic equation is

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0

3 years ago