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goblinko [34]
4 years ago
13

How do you divide 27 divided by 624 using partial quotients

Mathematics
1 answer:
Anni [7]4 years ago
6 0
The partial quotient of 624/27 is 23 remainders 3
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The box plot shows the daily attendance at a Fitness Class. What is the median?
Diano4ka-milaya [45]

Answer:

40

Step-by-step explanation:

The median is the middle line of the box, which is the value 40. The lower quartile would be 35 and the upper quartile being 50.

4 0
3 years ago
Find the slope of each graph. Express the answer in simplest form.help ​
Licemer1 [7]

Answer:

I think the slope is, as a point on the graph, (0,4).

Step-by-step explanation:

4 0
3 years ago
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Sonya made a graph showing the first ten minutes of her drive to the movies.
Agata [3.3K]

Answer:

A

Step-by-step explanation:

A. because the first point shows her acceleration and you can see her speed increasing when she hits the second point, so we can say that see accelerated up the ramp and after it hits the third point her speed becomes constant all the way when she reached the highway

4 0
3 years ago
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Catie earned $3,511.95 last month. She used 3/5 of her earnings to pay her bills. With the remaining money she bought two skirts
andrew11 [14]

Answer:

Amount \ left = 1345.81

Step-by-step explanation:

Total  \  earning = T= $3,511.95

Spent \ on \  Bills = B = \frac{3}{5} T = 2107.17

Remaining  \ amount = R = T-B = $3,511.95 - 2107.17\\R = 1404.78

Spent \ on \ Shopping = S = 2($21.99) + $14.99\\S = 58.97

Amount \ left = L = R - S\\Amount \ left = 1404.78 - 58.97\\Amount \ left = 1345.81

5 0
3 years ago
OOOO
lbvjy [14]

Step-by-step explanation:

Given bi-quadratic equation is:

x^4+95x^2 -500=0

Substituting x^2=a, given bi-quadratic equation reduces in the form of following quadratic equation:

a^2 +95a -500=0\\

Let us factorize the above quadratic equation:

a^2 +95a -500=0\\\therefore\: a^2 +100a -5a-500=0\\\therefore\: a(a +100) -5(a+100)=0\\\therefore\: (a +100)(a -5)=0\\\therefore\: (a +100)=0\:\: or \:\: (a -5)=0\\\therefore\: a = - 100\:\: or \:\: a = 5\\\\CASE\: (1)\:\\When\: a = - 100 \implies x^2 = - 100\\\therefore x=\pm \sqrt{-100}\\

Since square root of a negative number cannot be found, so:

x \neq \pm \sqrt{-100}\\

CASE\: (2)\:\\When\: a =5 \implies x^2 =5\\\therefore x=\pm \sqrt{5}\\

3 0
3 years ago
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