Answer:
The frequency is 
Explanation:
From the question we are told that
The energy required to ionize boron is 
Generally the ionization energy of boron pre atom is mathematically represented as
Here 
is the Avogadro's constant with value 
So
=> 
Generally the energy required to liberate one electron from an atom is equivalent to the ionization energy per atom and this mathematically represented as
=> 
Here h is the Planks constant with value 
So
=>
Answer:
[OH-] = 6.17 *10^-10
Explanation:
Step 1: Data given
pOH = 9.21
Step 2: Calculate [OH-]
pOH = -log [OH-] = 9.21
[OH-] = 10^-9.21
[OH-] = 6.17 *10^-10
Step 3: Check if it's correct
pOH + pH = 14
[H+]*[OH-] = 10^-14
pH = 14 - 9.21 = 4.79
[H+] = 10^-4.79
[H+] = 1.62 *10^-5
6.17 * 10^-10 * 1.62 * 10^-5 = 1* 10^-14
Answer:
B. ribosome
Explanation:
In the ribosomes, the codons get paired with anti codons to create a polypeptide or protein.
The activity series of metals as well as the electrode potential of metals can be used to compare the reactivity of metals.
<h3>What is used in comparing reactivity of metals?</h3>
The reactivity of metals can be compared using their electrode potentials which is a measures of the ability of the metal to donate electrons to another metal.
When comparing the reactivity of metals, the metal with the lesser negative electrode potential will be more reactive than another with a greater negative or positive electrode potential.
Therefore, the activity series of metals as well as the electrode potential of metals can be used to compare the reactivity of metals.
Learn more about activity series of metals at: brainly.com/question/17469010
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