Answer:
One way to find out is to change “passive mass” - the dirt and rocks of Earth - and convert it into “active mass” - add energy “E” to it. If we increase the energy “E” we will increase its mass. The key is, how do you turn “passive mass” into “active mass” by adding energy “E” to the “passive mass”? After all, isn’t “passive mass” of the Earth just the dirt and rocks that make up the planet?
Explanation:
Answer:
Option A = 14.19 atm
Explanation:
Given data:
Volume of gas = 2.50 L
Number of moles of gas = 1.35 mol
Temperature of gas = 320 K
Pressure of gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will put the values in formula.
P × 2.50 L = 1.35 mol × 0.0821 atm.L/ mol.K× 320
P = 35.467 atm.L/ 2.50 L
P = 14.19 atm
Thus, option A is correct.
The partial pressure of Ne is 1.06 atm. The answer is a. 1.1 atm
the formula for density is p=m/v
m aka the mass = 5.4; the v aka the volume = 8
so, p=5.4/8
p= 0.675 g/cm^3
*let's just say the mass' unit is gram so the unit for the density is g/cm^3
