Answer:
The Beer–Lambert law, also known as Beer's law, the Lambert–Beer law, or the Beer–Lambert–Bouguer law relates the attenuation of light to the properties of the material through which the light is travelling.
Explanation:
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The option that would be appropriate to model nuclear fission is disturbing a drop of water such that it breaks into smaller droplets
Nuclear fission refers to the splitting of a heavy nucleus into lighter nuclei owing to the bombardment of small particle.
The liquid drop model provides the most apt model for describing the concept of nuclear fission. In nuclear fission, the nucleus breaks due to the increase in repulsion between the nuclear charges.
As the size of the nucleus continues to increase, any little disruption will; result in the breaking up of the nucleus into smaller fragment called daughter nuclei.
Hence, the model of disturbing a drop of water such that it breaks into smaller droplets is the most apt description of nuclear fission.
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22.3 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.
To find the mass, the given data was,
Volume = 11.6 Liters
<h3>What is decomposition reaction?</h3>
A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.
In airbags, sodium azide decomposes to form sodium and nitrogen gas, which inflates the bag. The decomposition reaction is:
2 NaN₃ ⇒ 2 Na + 3 N₂
We can calculate the mass of NaN₃ needed to produce 11.6 L of N₂ at STP, using the following relations.
- At STP, 1 mole of N₂ occupies 22.4 L.
- The molar ratio of N₂ to NaN₃ is 3:2.
- The molar mass of NaN₃ is 65.01 g/mol.
Substituting all the known values to find the volume,
11.6 × ( 1 / 22.4) × ( 2/3) × ( 65.01 / 1)
= 22.4 g.
22.4 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.
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