Answer:
Explanation:
For discharge of capacitor in RC circuit , the relation is as follows
V is voltage across the capacitor , V₀ is maximum voltage across capacitor , λ is time constant and t is the time after which the voltage is recorded. During discharge this will also be voltage across resistance .
Taking log on both sides
lnV = lnV₀ - 
Given equation
[lnV] = - .027 t + 2.5
Comparing these equation
λ = 37 s
time constant = 37 sec.
Answer:
a. λ = 647.2 nm
b. I₀ 9.36 x 10⁻⁵
Explanation:
Given:
β = 56.0 rad , θ = 3.09 ° , γ = 0.170 mm = 0.170 x 10⁻³ m
a.
The wavelength of the radiation can be find using
β = 2 π / γ * sin θ
λ = [ 2π * γ * sin θ ] / β
λ = [ 2π * 0.107 x 10⁻³m * sin (3.09°) ] / 56.0 rad
λ = 647.14 x 10⁻⁹ m ⇒ λ = 647.2 nm
b.
The intensity of the central maximum I₀
I = I₀ (4 / β² ) * sin ( β / 2)²
I = I₀ (4 / 56.0²) * [ sin (56.0 /2) ]²
I = I₀ 9.36 x 10⁻⁵
$(0,,386. Sup apt g 9=6 ♂️
1.5 / 0.5 = 3 I believe this is the right answer
A longitudinal wave is also known as an oscillating wave. These waves affect the medium they are traveling through by disrupting what is either directly in front of behind them as they move.
