Answer:
g / 16
Explanation:
T = 2π 
angular frequency ω = 2π /T
= 
ω₁ /ω₂ = 
Putting the values
ω₁ = ω , ω₂ = ω / 4
ω₁ /ω₂ = 4
4 = 
g₂ = g / 16
option d is correct.
To solve this problem we will use the definition of the kinematic equations of centrifugal motion, using the constants of the gravitational acceleration of the moon and the radius of this star.
Centrifugal acceleration is determined by

Where,
v = Velocity
r = Radius
From the given data of the moon we know that gravity there is equivalent to

While the radius of the moon is given by

If we rearrange the function to find the speed we will have to



The speed for this to happen is 1.7km/s
Explanation:
a) How much work is done by gravity?
- w = f x d
- w = 950 x 10 x 5.5 = 52250j
b) How much work is done by tension?
- v²=u²+2as
- 0.75²=0.25²+2a x5.5
- 0.56=0.06+2a x5.5
- 2a x5.5 = 0.56 - 0.06
- 2a x 5.5 =0.5
- 11a=0.5
- a = 0.5/11 = 0.05m/s²
w = f x d
w = 950 x 0.05 x 5.5 = 261.25j