3 years ago

During 57 seconds of use, 330 C of charge flow through a microwave oven. Compute the size of the electric current.

Physics

1 answer:

swat323 years ago

3 0

Answer:

5.78amps

Explanation:

Given data

Time t= 57 seconds

Charge Q= 330C

Current I= ??

The expression for the electric current is given as

Q= It

Substituting we have

330= I*57

I= 330/57

I=5.78 amps

Hence the current is 5.78amps

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Answer:

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Explanation:

Given the following data;

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Substituting into the equation, we have

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Consider a situation where a constant force of 25 N acts on an object having a mass of 2 kg for 3 seconds. What is the work done

blagie [28]

Answer:

Work done W =1406.25 J

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Work done on a body can be calculated using newton's 2nd laws:

F=ma

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$\Rightarrow a=\frac{25}{2}=12.5m/s^2$

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Now work done is given by:

W=F.S

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W =1406.25 J

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3 years ago

In this first example of constant accelerated motion, we will simply consider a car that is initially traveling along a straight

algol13

Answer:

$v_{f} =25m/s$

Explanation:

Kinematics equation for constant acceleration:

$v_{f} =v_{o} + at=15+2*5=25m/s$

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