Answer:
3.77 Hz
Explanation:
The beat frequency that is heard can be calculated using the following equation:
<u>Where:</u>
f₁ = 110 Hz
<u>With:</u>
<em>T₁ = 594 N </em>
<em>T₂ = 554 N </em>
Hence, the beat frequency is:
Therefore, the beat frequency that is heard when the hammer strikes the two strings simultaneously is 3.77 Hz.
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The potential energy of the egg when it begins to fall is equal to the kinetic energy of the egg just before touching the ground:
m * g * h = (1/2) * m * v ^ 2
Clearing the speed:
v = root (2 * h * g)
Substituting the values
v = root (2 * (10) * (9.8)) = 14
Then, by definition, we have
F * deltat = m * deltav
Clearing F
F = (m * deltav) / (deltat)
Substituting the values
F = ((0.060) * (14)) / (2) = 0.42
answer
the force exerted on the egg by the floor was 0.42N
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D. because the statue has a new chemical called patina. It is no longer copper.