Answer:
u = 11.6 m/s
Explanation:
The end of a launch ramp is directed 63° above the horizontal. A skier attains a height of 10.9 m above the end of the ramp.
Maximum height, H = 10.9
Let v is the launch speed of the skier. The maximum height attained by the projectile is given by :


u = 11.6 m/s
So, the launch speed of the skier is 11.6 m/s. Hence, this is the required solution.
Answer:
41.3 m/s^2 option (e)
Explanation:
force, F = 6.81 N
mass, m = 165 g = 0.165 kg
Let a be the acceleration of the puck.
Use newtons' second law
Force = mass x acceleration
6.81 = 0.165 x a
a = 41.27 m/s^2
a = 41.3 m/s^2
Thus, the acceleration of the puck is 41.3 m/s^2.
Answer : Noble Gases do not readily form compounds because they are chemically stable with 8 valence electrons.
Explanation :
Noble gases are the chemical elements that are present in group 18 in the periodic table.
The elements are helium, neon, argon, krypton, xenon and radon.
They are chemically most stable except helium due to having the maximum number of 8 valence electrons can hold their outermost shell that means they have a complete octet.
They are rarely reacts with other elements to form compounds by gaining or losing electrons since they are already chemically stable.
Hence, the noble Gases do not readily form compounds because they are chemically stable with 8 valence electrons.
Answer:
If the frequency of the motion of a simple harmonic oscillator is doubled , then maximum speed of the oscillator changes by the factor 2
Explanation:
We know that in a simple harmonic oscillator the maximum speed is given by
= 
Here A is amplitude which is constant , so from above equation we see that maximum speed is directly proportional to
of the oscillation .
Since 
= 2
Where
is the maximum speed when frequency is doubled .
Answer:
2.87 km/s
Explanation:
radius of planet, R = 1.74 x 10^6 m
Mass of planet, M = 7.35 x 10^22 kg
height, h = 2.55 x 10^6 m
G = 6.67 x 106-11 Nm^2/kg^2
Use teh formula for acceleration due to gravity


g = 1.62 m/s^2
initial velocity, u = ?, h = 2.55 x 10^6 m , final velocity, v = 0
Use third equation of motion

0 = v² - 2 x 1.62 x 2.55 x 10^6
v² = 8262000
v = 2874.37 m/s
v = 2.87 km/s
Thus, the initial speed should be 2.87 km/s.