What is the density of a liquid that measures as 2 liters, and has a mass of 0.7 kilograms?

A drone flies 8 m/s due East with respects to the wind. The wind is blowing 6 m/s due North with respects to the ground. What is

vekshin1

Answer:

B. 10m/s

Explanation:

If a drone flies 8 m/s due East with respects to the wind and the wind is blowing 6 m/s due North, the speed of the drone with respect to the ground is its displacement.

Displacement is calculated using Pythagoras theorem.

d² = 8²+6²

d² = 64+36

d² = 100

Square root both sides

√d² = √100

d = 10m/s

Hence the distance of the drone with respect to the ground is 10m/s

Option B is correct

8 0

3 years ago

A plastic rod has been bent into a circle of radius R = 8.00 cm. It has a charge Q1 = +2.70 pC uniformly distributed along one-q

vovikov84 [41]

Answer:

Part a)

$V = -1.52 V$

Part b)

$V = -1.16 V$

Explanation:

Part a)

Electric potential is a scalar quantity

so here we can say that total potential due to a ring on its center is given as

$V = \frac{kQ}{R}$

here we know that

$Q = Q_1 - 6Q_1$

$Q = - 5 Q_1$

$Q_1 = 2.70 pC$

now we have

$V = \frac{(9\times 10^9)(-5\times 2.70 \times 10^{-12})}{0.08}$

$V = -1.52 V$

Part b)

Potential on the axis of the ring is given as

$V = \frac{kQ}{\sqrt{r^2 + R^2}}$

$V = \frac{(9\times 10^9)(-5\times 2.70\times 10^{-12})}{\sqrt{0.08^2 + 0.0671^2}}$

$V = -1.16 V$

8 0

3 years ago

The top of the syringe is a circle. You need to

Basile [38]

Answer:

3.60

Explanation:

8 0

3 years ago

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a proton travelling along is x-axis is lowed by a niform electric field E. at x = 20.0 cm, the proton has a speed of 3.5x10^6 m/

anzhelika [568]

Answer:

Magnitude of electric field is 1.06 x $10^5$ V/m along negative X-direction

Explanation:

Given: initial velocity of proton = u = 3.5 x $10^6$ m/s

final velocity of proton = v = 0 m/s

initial point $l_i$ = 0.2 m and final point is $l_f$ = 0.8 m

According to conservation of energy:

change in in kinetic energy = change in potential energy of proton

⇒ $\frac{m}{2}(v^2-u^2 ) = qE(l_i - l_f)$

where q and m is the charge and mass of proton E is the electric field , $l_i$ and $l_f$ is the initial and final position of proton

on substituting the respected values we get,

1.023 x $10^-^1^4$ = 9.6 x $10^-^2^0$ x E

⇒ E = 1.06 x $10^5$ V/m

external force is opposite to the motion as velocity of proton decreases with distance.

Therefore, magnitude of electric field is 1.06 x $10^5$ V/m along negative X-direction

5 0

3 years ago

A square boat made from iron has overall dimensions of 2.00 cm x 11.0 cm x 11.0 cm. It has a mass of 213 g. What is its density?

kupik [55]

<u>Answer:</u> The density of boat is $0.88g/cm^3$

<u>Explanation:</u>

To calculate the volume of boat, we use the equation:

$V=lbh$

where,

V = volume of boat

l = length of boat = 2.00 cm

b = breadth of boat = 11.0 cm

h = height of boat = 11.0 cm

Putting values in above equation, we get:

$V=2.00\times 11.0\times 11.0=242cm^3$

To calculate density of a substance, we use the equation:

$\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}$

We are given:

Mass of boat = 213 g

Volume of boat = $242cm^3$

Putting values in above equation, we get:

$\text{Density of boat}=\frac{213g}{242cm^3}\\\\\text{Density of boat}=0.88g/cm^3$

Hence, the density of boat is $0.88g/cm^3$

6 0

3 years ago

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