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Yuliya22 [10]
3 years ago
12

How many drops of water are in a 1.0 L bottle? (Hint: Start by estimating the diameter of a drop of water.)

Physics
2 answers:
o-na [289]3 years ago
7 0

Answer:

N = 2000 drops approx with 1 cm diameter each

Explanation:

Let the diameter of one drop is 1 cm

so volume of one drop is given by

V = \frac{1}{6}\pi d^3

now we have

V = \frac{1}{6}\pi(0.01)^3

V = 0.53 \times 10^{-6} m^3

now in 1L of liquid let say N drops are there

so we have

1L = 10^{-3} m^3

now we have

N = \frac{10^{-3}}{0.53 \times 10^{-6}}

N = 2\times 10^3

so it will have approx 2000 drops in it with diameter 1 cm each drop

pav-90 [236]3 years ago
7 0

The number of drops in water bottle  

Further Explanation:

The number of droplets present in one water bottle is given as the ratio of the total volume contained in the bottle to the volume of one droplet of the water present inside the bottle.

Consider that the diameter of one drop of water is 2\,{\text{mm}}.

Write the expression for the volume of one drop of water.

V = \dfrac{4}{3}\pi {\left( {\dfrac{d}{2}} \right)^3}    …… (I)                                                                                                    

Substitute the value of d in above expression.

\begin{aligned}V&= \frac{4}{3}\pi \left( {\frac{{2 \times {{10}^{ - 3}}\,{\text{m}}}}{2}} \right)\\&= 4.188 \times {10^{ - 9}}\,{{\text{m}}^{\text{3}}}\\\end{aligned}  

Convert the volume of one litre to {m^3}.

1\,l = {10^{ - 3}}\,{m^3}

Therefore, the number of water droplets present in 1\,l of water is.

\begin{aligned}n&= \frac{{{{10}^{ - 3}}\,{{\text{m}}^{\text{3}}}}}{{4.188 \times {{10}^{ - 9}}\,{{\text{m}}^{\text{3}}}}}\\&= 2.38 \times {10^5}\,{\text{droplets}} \\ \end{aligned}  

Thus, the number of droplets present in the bottle of one litre water is \boxed{2.38 \times {{10}^5}} droplets.

Learn More:

  1. The amount of kinetic energy an object has depends on its brainly.com/question/137098
  2. A 30.0-kg box is being pulled across a carpeted floor by a horizontal force of 230 n , against a friction force of 210 n brainly.com/question/4033012
  3. A property is a characteristic of a substance that can be observed and does not change the identity of the substance brainly.com/question/859623

Answer Details:

Grade: College

Chapter: Units and Measurement

Subject: Physics

Keywords: Drops of water, 1.0L water, bottle, diameter of drop, volume of drop, number of droplets, in bottle.

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Jeff's body contains about 5.46 L of blood that has a density of 1060 kg/m3. Approximately 45.0% (by mass) of the blood is cells
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Answer:

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b

The number of blood cells is  N_t=1.04*10^{13}

Explanation:

From the question we are told that

         The volume of blood  is  V_b = 5.46 \ L = \frac{5.46}{1000} = 0.00546m^3

         The density of the blood is  \rho_b = 1060 kg/m^3

         % of blood  that is  cell is  = 45.0%

        % of the blood that is  plasma is  = 55.0%

        density of blood cell is  \rho_d = 1125kg/m^3

        % of cell that are white is  = 1%

        % of cell that is red is  = 99%

        The diameter of the red blood cell is  = 7.5 \mu m = 7.5*10^{-6}m

         The radius of the red blood cell is  = \frac{7.5*10^{-6}}{2} = 3.75*10^{-6}m

Generally the mass is mathematically  represented as

               m = \rho_b * V_b

Substituting value

            m = 1060 * 0.00546

               m= 5.7876kg

Mass of cell is m_c = 45% of m

                         = 0.45 * 5,7876

                         = 2.60442 kg

The volume of cells is V_c = \frac{m_c}{\rho_d}

                                      = \frac{2.60442}{1125}

                                      = 2.315 *10^{-3} m^3

The volume of white blood cell is V_w = 1% of volume of cells

                                                         = \frac{1}{100} * 2.315*10^{-3}

                                                       = 2.315*10^{-5}m^3

The volume of a single cell is V_s = 4 \pi r^3

                                                                        = 4*(3.142) * (3.75*10^{-6})^3

                                                                        = 2.21*10^{-16}m^3

The volume of red blood cells is V_r = V_c - V_w

                                                           =2.315*10^{-3} - 2.315*10^{-5}

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The number of red blood cell is  = \frac{V_r}{V_s}

                                                     = \frac{2.29 *10^{-3}}{2.21*10^{-16}}

                                                    = 1.037*10^{13}

The Number of white blood cell is   =\frac{V_w}{V_s}

                                                          = \frac{2.315 * 10^{-5}}{2.21*10^{-16}}

                                                          = 1.04*10^{11}

The total number of blood cells is  N_t= 1.037*10^{13} + 1.04*10^{11}

                                                        N_t=1.04*10^{13}

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