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2 years ago

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A researcher finds that blood alcohol levels cause Progressive damage the liver all of mice and his study were fed the same amou

nt and types of food different consideration of alcohol injected into different mice represents the

1 answer:

Juli2301 [7.4K]2 years ago

4 0

Answer:hmm

Explanation:

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A 10,000-kg railroad car travels down the track at 30 m/s and hits a second stationary railroad car of 20,000 kg. The cars becom

Ivanshal [37]

Answer:

10 m/s

Explanation:

The problem can be solved by using the law of conservation of momentum: the initial momentum has to be equal to the final momentum, so we can write the following

$p_i = p_f$

$m_1 u_1 + m_2 u_2 = (m_1 +m_2 )v$

where

$m_1 = 10,000 kg$ is the mass of the first car

$u_1=30 m/s$ is the initial velocity of the first car

$m_2 = 20,000 kg$ is the mass of the second car

$u_2 = 0$ is the initial velocity of the second car

$v$ is the final velocity of the two combined cars after the collision

Re-arranging the equation and substituting the numbers, we find

$v=\frac{m_1 u_1 +m_2 u_2}{m_1+m_2}=\frac{(10,000)(30)-0}{10,000+20,000}=10 m/s$

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3 years ago

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I NEED. HELP PLEASE, THANKS! :)<br> Describe each Newton Law.

SSSSS [86.1K]

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction

Explanation:

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3 years ago

Using .125 mass kgwhat is the velocity

agasfer [191]

Answer:

The answer is 5 meters per second.

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3 years ago

A flat loop of wire consisting of a single turn ofcross-sectional area 7.90 cm2is perpendicular to a magnetic field that increas

Westkost [7]

To develop this problem, it is necessary to apply the concepts related to Faraday's law and Magnetic Flow, which is defined as the change that the magnetic field has in a given area. In other words

$\Phi = BA Cos\theta$

Where

B= Magnetic Field

A = Area

$\theta =$ Angle between magnetic field lines and normal to the area

The differentiation of this value allows us to obtain in turn the induced emf or electromotive force.

In this case we have that the flat loop of wire is perpendicular to the magnetic field, therefore the angle is 0 degrees, since its magnetic field acts parallel to the area:

$\theta =$ 0 then our expression can be written as

$\Phi = BA$

From the same value of the electromotive force we have to

$\epsilon = -\frac{d\Phi}{dt}$

Replacing we have

$\epsilon = -A\frac{B}{dt}$

Replacing with our values we have that

$\epsilon = -(7.9*10^{-4}m)\frac{(3.5-0.5)}{0.1}$

$\epsilon = -0.0237V$

Therefore the magnitude of the induced emf in the loop is 0.0237V

On the other hand we have that the current by Ohm's Law can be defined as

$I = \frac{\epsilon}{R}$

For the given value of the resistance and the previously found potential we have to

$I = \frac{0.237}{1.3}$

$I= 0.0182A$

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3 years ago

QUESTION 1 What is defined as anything made up of atoms that has mass and takes up space?

grandymaker [24]

Matter is the answer.

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2 years ago

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