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solniwko [45]
3 years ago
5

Two speakers are spaced 15 m apart and are both producing an identical sound wave. You are standing at a spot as pictured. What

would be the frequency produced by the speakers to create perfectly constructive interference? Assume n = 1 and v = 343 m/s
Physics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

Frequency is 213.04\ s^{-1}.

Explanation:

Distance between source 1 from the receiver , S_1 =\sqrt{10^2+22^2}=24.17\ m.

Distance between source 2 from the receiver , S_2=\sqrt{5^2+22^2}=22.56\ m.

Now ,

Path difference , r = S_1-S_2=24.17-22.56=1.61\ m.

We know, for constructive interference path difference should be integral multiple of wavelength .  

Therefore, r=n\times \lambda

It is given that n = 1,

Therefore, \lambda=1.61\ m.

Frequency can be found by , \nu=\dfrac{v}{\lambda}= \dfrac{343}{1.61}=   213.04\ s^{-1} .

Hence, this is the required solution.

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