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nata0808 [166]
3 years ago
6

How can humans activities affect the frequency and impact of natural disasters

Physics
2 answers:
denpristay [2]3 years ago
8 0
Forest fires can be an impact 

Mkey [24]3 years ago
5 0

Answer:

Human activities affect the frequency and impact of natural disasters because of urbanization, deforestation, waste disposal, resource extraction, man-made structures, and greenhouse gases.

Explanation:

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The electrons can be modeled as forming a uniform shell of negative charge. What net electric field do they produce at the locat
Nonamiya [84]

Answer:

E=0

Explanation:

The electric field at the centre of the shell is zero because total enclosed charge in the nucleus is zero

7 0
3 years ago
A turtle ambles leisurely, as turtles tend to do, when it moves from a location with position vector 1,=1.91 m and 1,=−2.73 m in
Elena-2011 [213]

Answer:

Components: 0.0057, -0.0068. Magnitude: 0.0089 m/s

Explanation:

The displacement in the x-direction is:

d_x = 3.65-1.91=1.74 m

While the displacement in the y-direction is:

d_y = -4.79 -(-2.73)=-2.06 m

The time taken is t = 304 s.

So the components of the average velocity are:

v_x = \frac{d_x}{t}=\frac{1.74}{304}=0.0057 m/s

v_y = \frac{d_y}{t}=\frac{-2.06}{304}=-0.0068 m/s

And the magnitude of the average velocity is

v=\sqrt{v_x^2+v_y^2}=\sqrt{(0.0057)^2+(-0.0068)^2}=0.0089 m/s

8 0
3 years ago
When going from a fast speed to a slow speed how is light bent?
Zolol [24]
Toward the normal line
4 0
3 years ago
Read 2 more answers
Which statement is true according to Newton's first law of motion?
lys-0071 [83]
An object in motion tends to stay in motion an oject at rest stays at rest.
5 0
3 years ago
The noise from a power mower was measured at 106 dB. The noise level at a rock concert was measured at 115 dB. Find the ratio of
andrey2020 [161]

Answer:

= 8

Explanation:

noise from power mower = 106 dB

noise from rock concert = 115 dB

we would be applying the formula for the decibel level of sound to get the intensities.

(B) = 10 log \frac{I}{I₀}

I = intensity of sound

I₀= reference intensity = 10^{-12} W/m^{2}

  • intensity of the power mower

106 = 10 log \frac{I}{10^{-12}}

10.6 =  log \frac{I}{10^{-12}}

10^{10.6} = \frac{I}{10^{-12}}

I = 10^{10.6} x 10^{-12}

I of power mower = 0.0398 W/m^{2}

  • intensity of the rock music

115 = 10 log \frac{I}{10^{-12}}

11.5 =  log \frac{I}{10^{-12}}

10^{11.5} = \frac{I}{10^{-12}}

I = 10^{11.5}  x 10^{-12}

I of rock music = 0.316 W/m^{2}

now the ratio of the intensity of the rock music to the power mower

= \frac{0.316}{0.0398}

= 8

4 0
3 years ago
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