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nata0808 [166]
3 years ago
6

How can humans activities affect the frequency and impact of natural disasters

Physics
2 answers:
denpristay [2]3 years ago
8 0
Forest fires can be an impact 

Mkey [24]3 years ago
5 0

Answer:

Human activities affect the frequency and impact of natural disasters because of urbanization, deforestation, waste disposal, resource extraction, man-made structures, and greenhouse gases.

Explanation:

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4 0
4 years ago
"If E = 7.50V and r=0.45Ω, find the minimum value of the voltmeter resistance RV for which the voltmeter reading is within 1.0%
Virty [35]

Answer:

The  minimum value is R_V =44.552\  \Omega

Explanation:

From the question we are given that

                  The voltage is E = 7.5V

                  The internal  resistance is r = 0.45

The objective of this solution is to obtain the minimum value of the voltmeter resistance for which the voltmeter reading is within 1.0% of the emf of the battery

  What is means is that we need to obtain voltmeter resistance such that

                                V = (100% -1%) of E

Where E  is the  e.m.f of the battery and V is the voltmeter reading

                          i.e    V = 99% of E = 0.99 E = 7.425  

Generally

                E = V + ir

     where ir is the internal potential difference of the voltmeter and

                V is the voltmeter reading

 Making i the subject of the formula above

            i = \frac{(E-V)}{r}

               =\frac{7.50-7.425}{0.45}

              = 0.1667 A

Now the current is constant through out the circuit so,

                  V = iR_V

Where  R_V is the value of voltmeter resistance

                Hence R_V = \frac{V}{i}  = \frac{7.425}{0.1667}

                                  =44.552\  \Omega

                       

8 0
3 years ago
Light in vacuum is incident on the surface of a glass slab. In the vacuum the beam makes an angle of 38.0° with the normal to th
iren [92.7K]

Answer:

n_glass = 1.404

Explanation:

In order to calculate the index of refraction of the light you use the Snell's law, which is given by the following formula:

n_1sin\theta_1=n_2sin\theta_2         (1)

n1: index of refraction of vacuum = 1.00

θ1: angle of the incident light respect to normal of the surface = 38.0°

n2: index of refraction of glass = ?

θ2: angle of the refracted light in the glass respect to normal = 26.0°

You solve the equation (1) for n2 and replace the values of all parameters:

n_2=n_1\frac{sin\theta_1}{sin\theta_2}=(1.00)\frac{sin(38.0\°)}{sin(26.0\°)}\\\\n_2=1.404

The index of refraction of the glass is 1.404

3 0
3 years ago
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