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algol13
3 years ago
12

Compare the two ratios by entering >, < , or = in the box 6:15 30:80

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
7 0
Compare <span>6:15 30:80
or you can write </span><span>6/15 and 30/80

6/15 = 0.4
30/80 = 0.375

answer </span><span>6:15 > 30:80</span><span>

</span>
You might be interested in
Kaylee put $240.00 in a bank account that gains 25%
creativ13 [48]

Answer:

S=720

Step-by-step explanation:

25$ of 240 =60

60×12months=720

5 0
3 years ago
Given f(x) = (lnx)^3 find the line tangent to f at x = 3
kirill [66]
Explanation

We must the tangent line at x = 3 of the function:

f(x)=(\ln x)^3.

The tangent line is given by:

y=m*(x-h)+k.

Where:

• m is the slope of the tangent line of f(x) at x = h,

,

• k = f(h) is the value of the function at x = h.

In this case, we have h = 3.

1) First, we compute the derivative of f(x):

f^{\prime}(x)=\frac{d}{dx}((\ln x)^3)=3*(\ln x)^2*\frac{d}{dx}(\ln x)=3*(\ln x)^2*\frac{1}{x}=\frac{3(\ln x)^2}{x}.

2) By evaluating the result of f'(x) at x = h = 3, we get:

m=f^{\prime}(3)=\frac{3}{3}*(\ln3)^2=(\ln3)^2.

3) The value of k is:

k=f(3)=(\ln3)^3

4) Replacing the values of m, h and k in the general equation of the tangent line, we get:

y=(\ln3)^2*(x-3)+(\ln3)^3.

Plotting the function f(x) and the tangent line we verify that our result is correct:

Answer

The equation of the tangent line to f(x) and x = 3 is:

y=(\ln3)^2*(x-3)+(\ln3)^3

6 0
1 year ago
In the figure angle 2 and angle 3 are
anygoal [31]
I believe it’s c) complementary
6 0
2 years ago
In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 4x – 5, and HE = 2y + 3. Find the values of x and y.
marissa [1.9K]

Here, DH = HF 

x+3 = 3y

x = 3y-3   ----(I)

GH = HE

4x-5 = 2y+3

4x = 2y+8

Substitute value of x,

4(3y-3) = 2y+8

12y-12 = 2y+8

12y-2y = 12+8

10y = 20

y = 2

Now, substitute it in equation 1,

x = 3(2)-3

x = 6-3 = 3

So, your final answer is      x=3  & y=2



3 0
3 years ago
Read 2 more answers
A manufacturer of bicycles has determined that 550 bikes per month will be sold at a price of $250. At a price of $150, it is es
iogann1982 [59]

750 bikes would be sold for $350

Let x represent the number of bikes sold per month and y represent the price.

550 bikes are sold at a price of $250, this can be represented by (550, 250). Also, 750 bikes is sold at a price of $150, hence it is represented by (750, 150)

A linear function is represented by:

y = mx + b

m is the slope, b is the y intercept.

Therefore the function is:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-250=\frac{150-250}{750-550}  (x-550)\\\\y=\frac{1}{2}x-25

The number of bikes sold for $350 is:

350 = (1/2)x - 25

x = 750

Therefore 750 bikes would be sold for $350

Find out more at: brainly.com/question/13911928

3 0
2 years ago
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