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stealth61 [152]
3 years ago
9

the soccer team is planning to sell health bars for a fundraiser. the prices of purchasing health bars from two different compan

ies are represented by the system of equations shown, where x is the number of bars purchased and y is the total cost in dollars. company a: y = 0.75x company b: y = 10 0.50x how many bars would the team need to purchase from each company in order for the total cost to be equal?
Mathematics
2 answers:
zubka84 [21]3 years ago
4 0
40 bars __________________
k0ka [10]3 years ago
4 0

Answer:

The team needs to buy 40 health bars.

Step-by-step explanation:

We are given that,

Number of bars purchased = x

Total cost of the bars = y (in dollars)

The prices of purchasing health bars from different companies are given by,

Company A: y = 0.75x

Company B: y = 10+0.50x

Now, the teams needs to find the number of bars so that the cost are equal.

That is, we get,

0.75x=10+0.50x\\0.25x=10\\x=40

Hence, the team needs to buy 40 health bars.

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You travel from point A to point B in a car moving at a constant speed of 70 km/h. Then you travel the same distance from point
tankabanditka [31]

Answer:

Yes, the average speed for the entire trip from A to C is equal to 80\frac{km}{h}

Step-by-step explanation:

The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time. For the special case of straight line motion in the x direction, the average velocity takes the form:

V_a_v_e_r_a_g_e=\frac{x_2-x_1}{t_2-t_1}=\frac{Δx}{Δt}

If the beginning and ending velocities for the motion are known, and the acceleration is constant, the average velocity can also be expressed as:

V_a_v_e_r_a_g_e=\frac{V_1+V_2}{2}

We Know that:

V_1=70\frac{km}{h} \\\\V_2=90\frac{km}{h}

Replacing the values:

V_a_v_e_r_a_g_e=\frac{70+90}{2} =\frac{160}{2}=80\frac{km}{h}

5 0
3 years ago
For each function shown:
mestny [16]
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6 0
2 years ago
In an 18-meter race between a tortoise and a hare, the tortoise leaves 23 minutes before the hare. The hare, by running at an av
seropon [69]
We know that:
time=distance/speed
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3 years ago
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