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VARVARA [1.3K]
2 years ago
8

Y=-3+6and y=1/3x-8 determine if the equation are parallel, perpendicular or neither

Mathematics
1 answer:
Gelneren [198K]2 years ago
7 0

Slope intercept form: y = mx + b

m = slope and b = y-intercept

The equation is: y = -3x + 6

The m value for this is -3, so the line has a slope of -3. If y = 1/3x - 8 was parallel to y = -3x + 6 then they would have the same slope, which they do not. So they aren't parallel.

The find the slope of a perpendicular line, take the negative reciprocal of the slope of y = -3x + 6. The negative reciprocal of -3 is 1/3.  y = 1/3x - 8 has a slope of 1/3, so they are perpendicular to each other.

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Plz answer correctly both questions if do will give brainliest!!!!
Marina86 [1]
54 square inches
Basically you just multiply
6 0
2 years ago
Read 2 more answers
A garrison of 400men had food for 40days.After 10 days,200 more men joined them .How long will the food last now?(Assume that th
mestny [16]

Let x be the amount of food needed for one man for one day. At the beginning, we have enough food for 400 men for 40 days, i.e.

400\cdot 40\cdot x = 16000x

After 10 days, the 400 men will have consumed

400\cdot 10\cdot x = 4000x

food, impliying that the food remaining is

16000x-4000x=12000x

If 200 more men join the garrison, there are now 600 men. Each of them requires x food each day, and there are 12000x units of food remaining. They will last

\dfrac{12000x}{600}=20 days.

6 0
3 years ago
Students in a zoology class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. After t​
juin [17]

Answer:

a. 73; b. 48.9; c. 2; d. 33.8; e. 73

Step-by-step explanation:

Assume the function was

S(t)= 73 - 15 ln(t + 1), t  ≥ 0

a. Average score at t = 0

S(0) = 73 - 15 ln(0 + 1) = 73 - 15 ln(1) = 73 - 15(0) =73 - 0 = 73

b. Average score at t = 4

S(4) = 73 - 15 ln(4 + 1) = 73 - 15 ln(5) = 73 - 15(1.61) =73 - 24.14 = 48.9

c. Average score at t =24

S(24) = 73 - 15 ln(24 + 1) = 73 - 15 ln(25) = 73 - 15(3.22) =73 - 48.28 = 24.7

d. Percent of answers retained

At t = 0. the students retained 73 % of the answers.

At t = 24, they retained 24.7 % of the answers.

\text{Percent retention} = \dfrac{\text{24.7}}{\text{73}} \times 100 \, \% = \text{33.8 \%}\\\\\text{The students retained $\large \boxed{\mathbf{33.8 \, \%}}$ of their original knowledge after two years.}

e. Maximum of the function

The maximum of the function is at t= 0.

Max = 73 %

The graph below shows your knowledge decay curve. Knowledge decays rapidly at first but slows as time goes on.

 

6 0
2 years ago
Which expression is equivalent to the given polynomial expression?
PilotLPTM [1.2K]

Answer:

-4 a^2 - 3 b

Step-by-step explanation:

8 0
3 years ago
Rewrite 19/5 as a mixed number.
Ugo [173]
 19/5 as a mixed number is 3 4/5.
3 0
3 years ago
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