When did galileo discover projectile motion?

The gravitational force between two asteroids is 2.59 × 10 (exponent)-6 N. The centers of mass are 2000 meters away and their ma

makkiz [27]

Answer:

$2.79 \times 10^5 \ \text{kg}$

Explanation:

Newton's Law of Universal Gravitation:

$$F= G\frac{m_1 m_2}{r^2}$
F = force of gravity (N)
G = gravitational constant $(6.67 \times 10^-^1^1 \ N\frac{m^2}{kg^2})$
$m_1$ = mass of Object 1 (kg)
$m_2$ = mass of Object 2 (kg)
r = distance between the center of mass (m)

Let's convert our given information to scientific notation:

$2000 \ m \rightarrow 2.0 \times 10^3 \ m$

Now using the gravitational force and the distance between centers of mass that are given, we can plug these into Newton's law:

$2.59 \times 10^-^6 $\ N = 6.67 \times 10^-^1^1 \ N \frac{m^2}{kg^2} \times \frac{m_1 m_2}{(2.0 \times 10^3 \ m)^2}$

Remove the units for better readability.

$2.59 \times 10^-^6=6.67 \times 10^-^1^1 \frac{m_1m_2}{(2.0 \times 10^3)^2}$

Divide both sides of the equation by the gravitational constant G.

$\frac{2.59 \times 10^-^6}{6.67 \times 10^-^1^1} =\frac{m_1m_2}{(2.0 \times 10^3)^2}$

Distribute the power of 2 inside the parentheses.

$\frac{2.59 \times 10^-^6}{6.67 \times 10^-^1^1} =\frac{m_1m_2}{2.0 \times 10^6}$

If we evaluate the left side of the equation, we get:

$3.88305847 \times 10^4 = \frac{m_1m_2}{2.0 \times 10^6}$

Multiply both sides of the equation by r.

$7.76611694 \times 10^1^0= m_1m_2$

In order to find the mass of one asteroid, we can use the fact that both asteroids have the same mass, therefore, we can rewrite $m_1m_2$ as $m^2$ .

$7.76611694 \times 10^1^0= m^2$

Square root both sides of the equation.

$m=\sqrt{7.76611694 \times 10^1^0}$

$m=2.78677536 \times 10^5$
$m=2.79 \times 10^5$

Since m is in units of kg, we can state that the mass of each asteroid is 2.79 * 10⁵ kg.

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geniusboy [140]

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3 years ago

what is the minimum (nonzero) thickness of the coating for which there is maximum transmission of the light into the rod?

timofeeve [1]

The thickness is 155 nm at t1.

The thickness is 77.3 nm at t2.

The inquiry informs us that the laser light's wavelength is λ=510nm

The plastic rod's refractive index is n=1.30

The transparent coating's refractive index is nr=1.65

Minimum reflection would be required for maximal light transmission into the rod, and it is mathematically described as

2t1=510+10⁻⁹/1.65

t1=510+10⁻⁹/1.65*2

t1=155nm

where m is the interference order, which equals 1.

2t2= {m+1/2} λ/nr

The thickness is t replacing values

t1=155 nm

The highest reflection would occur for minimal light penetration through the rod, and this maximum reflection is mathematically described as

2t2= [m+1/2] λ/nr

t2=77.3 nm

The complete question is- Laser light of wavelength 510 nm is traveling in air and shines at normal incidence onto the flat end of a transparent plastic rod that has n = 1.30. The end of the rod has a thin coating of a transparent material that has refractive index 1.65. What is the minimum (nonzero) thickness of the coating (a) for which there is maximum transmission of the light into the rod; (b) for which transmission into the rod is minimized?

Learn more about reflection here-

brainly.com/question/15487308

#SPJ4

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