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postnew [5]
3 years ago
13

How many total atoms are in 0.250 g of p2o5?

Physics
2 answers:
sasho [114]3 years ago
5 0
There are 2 P atoms and 5 O atoms which results in a total of 7 atoms per molecule. Hope this helps you out; I had the same question yesterday on my 9th grade Physical Science test. 
  
Strike441 [17]3 years ago
3 0

Answer:

3.71 × 10²¹ atoms

Explanation:

The molar mass of P₂O₅ is 283.89 g/mol. The moles of P₂O₅ corresponding to 0.250 g of P₂O₅ are:

0.250 g × (1 mol/283.89 g) = 8.81 × 10⁻⁴ mol

In 1 mole of P₂O₅ there are 6.02 × 10²³ molecules of P₂O₅ (Avogadro's number). In 8.81 × 10⁻⁴ moles of P₂O₅, the molecules of P₂O₅ are:

8.81 × 10⁻⁴ mol × (6.02 × 10²³ molecule/ 1 mol) = 5.30 × 10²⁰ molecule

In 1 molecule of P₂O₅, there are 7 atoms (2 atoms of P and 5 atoms of O). In 5.30 × 10²⁰ molecules of P₂O₅, the number of atoms is:

5.30 × 10²⁰ molecule × (7 atom/1 molecule) = 3.71 × 10²¹ atom

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4 0
3 years ago
A ball is thrown horizontally from the top of a building 14.9 m high. The ball strikes the ground at a point 107 m from the base
umka2103 [35]

Answer:

1) t=1.743 sec

2)Vo=61.388  m/sec

3)the x component of its velocity just be- fore it strikes the ground is the same as the  initial velocity of the ball that is=61.388  m/sec

4)Vf=17.08 m/s

Explanation:

1)From second equation of motion we get

h=Vit+(1/2)gt^2

here in case(a): Vi=0 m/s,h=14.9m,,put these values in above equation to find the time the ball is in motion

14.9=(0)*t+(1/2)(9.8)t^2

t^2=14.9/4.9

t^2=3.040 sec

t=1.743 sec

2) s=Vo*t

Putting values we get

107=Vo*1.743

Vo=61.388  m/sec

3)the x component of its velocity just be- fore it strikes the ground is the same as the  initial velocity of the ball that is=61.388  m/sec

4)From third equation of motion we know that

Vf^2-Vi^2=2gh

here Vi=0 m/s,h=14.9 m

Vf^2=Vi^2+2gh=0+2(9.8)(14.9)

Vf^2=292.04

Vf=17.08 m/s

8 0
3 years ago
A mineral has a mas of 53grams. Its volume is 12millileters. What is the<br> density?
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Explanation:

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3 years ago
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How are gas particles arranged in a container?
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Answer:

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Explanation:

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4 0
3 years ago
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A spherical balloon has a radius of 6.55 m and is filled with helium. The density of helium is 0.179 kg/m3, and the density of a
Ksju [112]

Answer:

M_1 = 317.7 kg

Explanation:

Mass of the helium gas filled inside the volume of balloon is given as

m = \rho V

m = 0.179(\frac{4}{3}\pi R^3)

m = 0.179(\frac{4}{3}\pi 6.55^3)

m = 210.7 kg

now total mass of balloon + helium inside balloon is given as

M = 210.7 + 990

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now we know that total weight of balloon + cargo = buoyancy force on the balloon

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1200.7 + M_1 = 1518.4

M_1 = 317.7 kg

3 0
3 years ago
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