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Vadim26 [7]
3 years ago
5

What do we call the days when the sun is directly overhead the equator?

Physics
1 answer:
NikAS [45]3 years ago
8 0

Answer:

Equinox

Explanation:

It is an astronomical phenomenon that is repeated twice a year, in summer and winter, and that is caused because the axis on which our planet rotates is slightly inclined with respect to the plane of translation, this is its trajectory around the Sun.

For this reason there are two equinoxes a year, a phenomenon completely opposite to the solstice, but also marks the beginning of the spring and autumn seasons.

The equinoxes occur around March 20 or 21 and September 22 or 23, and it is the days when the Sun is exactly over the equator, which makes day and night more or less the same duration. The word ‘equinox’ comes from Latin and means precisely ‘same night’. In those two moments the part of the Earth closest to the Sun is the equator.

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What is the half life-life of your 100 atoms of Carbon-14?
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a car takes 125 ft to brake from 60 to 0 mph. Assume that the acceleration of the Prius is constant while braking. Find how long
max2010maxim [7]

Answer:

2.84 seconds

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t = ?

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Read 2 more answers
Una partícula se mueve en el plano XY efectúa un desplazamiento mientras actúa sobre ella una fuerza constante. X= (4i + 3j) m,
dsp73

Answer:

a) La magnitud del desplazamiento es de 5 m

La magnitud de la fuerza es 20 N

b) El trabajo realizado por la fuerza es de 100 J

c) El ángulo entre la fuerza y el plano es 0 °

Explanation:

a) La magnitud del desplazamiento se encuentra por la relación;

\left | X \right | = \sqrt{X_{x}^{2}+X_{y}^{2}}

Lo que da;

\left | X \right | = \sqrt{4^{2}+3^{2}} = 5 \ m

De manera similar, la magnitud de la fuerza, F, se encuentra como sigue;

\left | F \right | = \sqrt{F_{x}^{2}+F_{y}^{2}}

Lo que da;

\left | F \right | = \sqrt{16^{2}+12^{2}} = 20 \ N

b) El trabajo, W, realizado por la fuerza = Fuerza, F × Distancia, X

∴ Ancho = 20 N × 5 m = 100 N · m = 100 J

c) La dirección de la fuerza viene dada por la siguiente fórmula;

tan^{-1} \left (\dfrac{F_y}{F_x} \right ) = tan^{-1} \left (\dfrac{12}{16} \right )  = 38.9^{\circ}

La dirección del plano viene dada por la siguiente fórmula;

tan^{-1} \left (\dfrac{X_y}{X_x} \right ) = tan^{-1} \left (\dfrac{3}{4} \right )  = 38.9^{\circ}

Por tanto, el ángulo entre la fuerza y el plano = 0 °

La fuerza actúa a lo largo del plano.

6 0
3 years ago
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