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pantera1 [17]
4 years ago
11

What is the greatest possible error for each measurement?

Mathematics
2 answers:
AysviL [449]4 years ago
7 0
A. 0.001

B. 5

C. 9.045
 
D.0.50
 I am not sure though, so don't hurry writing it down. I didn't really understand what you were asking so I just guessed that you want something like this.

nignag [31]4 years ago
4 0
The greatest possible error of 18.9m is 18.95m - 18.85m = 0.1m
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Use the information in the table to find the indicated probability.
grin007 [14]

Answer:

P(\text{Female}|\text{Advanced})=\frac{322}{567}\approx0.5679

Step-by-step explanation:

\displaystyle P(\text{Female}|\text{Advanced})=\frac{P(\text{Female and Advanced})}{P(\text{Advanced})}\\\\P(\text{Female}|\text{Advanced})=\frac{\frac{322}{2501}}{\frac{567}{2501}}\\\\P(\text{Female}|\text{Advanced})=\frac{322}{567}\\ \\P(\text{Female}|\text{Advanced})\approx0.5679

5 0
3 years ago
Which of the following represents f(-3)? <br><br>A: 7 <br><br>B: 5 <br><br>C: 1 <br><br>D: -1 <br>​
Fed [463]

Answer:

f(-3)=-1

Step-by-step explanation:

-3 is less than 0, so you are going to use f(x)=x+2.

Plug in values:

f(-3)=-3+2\\f(-3)=-1

7 0
3 years ago
Read 2 more answers
BRAINLIESTTT ASAP!!! PLEASE HELP ME :)
Ronch [10]

Answer:

○ x³\⁷

Step-by-step explanation:

Since you are multiplying ⁷√x three times, you write it like this first, ⁷√x³, then according to one of the Six Exponential Rules, ⁿ√aᵐ = aᵐ\ⁿ, ⁷√x³ gets rewritten as x³\⁷.

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

**In one of my You-Tube videos, it talks about all six exponential rules. The video is titled "Six Exponential Rules". Go check it out and get as much assistance as you can from the tutorial.

4 0
3 years ago
Please help me with this problem
Norma-Jean [14]

Answer:

Answer is 544

Hope it helps you

3 0
2 years ago
Find an equation of the tangent line to the curve at the point (1,1/e). y=x^4*e^-x
jarptica [38.1K]
We will use <span>y-y1=m(x-x1), where m= f '(x)= 4x^3e^-x - x^4e^-x, f ' (1) =3e^-1
</span>f  (1) =4e^-1
so the equation of tangent line tothe curve at the point <span>(1,1/e) is 
y= </span>3e^-1(x-1) + 4e^-1, or y= 3e^-1(x)) + e^-1, 
7 0
3 years ago
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