Answer:
0.9009
Step-by-step explanation:
Let X be the event that Current will flow
Let Y be the event that the first relay which is 1 is closed
Thus, we can say that every element of Y is in X, but X possesses more elements. Thus, Y ⊂ X.
Thus, we can say that;
P(X ∩ Y) = P(Y)
Thus, given that current flowed, the probability that relay 1 functioned will be expressed as;
P(Y | X) = (P(Y ∩ X))/P(X)
From earlier, we saw that P(X ∩ Y) = P(Y). Thus;
P(Y | X) = P(Y)/P(X)
From the question, P(Y) = 0.9
Since there are 3 relays, then we have;
P(X) = 1 - 0.1³ = 0.999
Thus;
P(Y | X) = 0.9/0.999
P(Y | X) = 0.9009
Answer:
-5
Step-by-step explanation:
3x²y + xy²
Let x = -1/2 and y = 4
3(-1/2)^2 (4) + (-1/2) (4)^2
Exponents first
3(1/4) (4) + (-1/2) 16
Multiply
3 - 8
Subtract
-5
Answer:
34.5 ft
Step-by-step explanation:
~Refer to the attachment for the solution.
Step-by-step explanation:
<h3>
<em><u>Given</u></em><em><u>:</u></em></h3>
Length of the rectangle = 6.5 m
Width of the rectangule = 7.3 m
<h3>
<em><u>Then</u></em><em><u>:</u></em></h3>
<u>First</u><u> </u><u>case</u><u>,</u>
Area of the rectangle
= length × width
= 6.5 m × 7.3 m
= <em><u>47.45</u></em><em><u> </u></em><em><u>s</u></em><em><u>q</u></em><em><u>.</u></em><em><u>m</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em><em><u>(</u></em><em><u>i</u></em><em><u>)</u></em>
<u>Second</u><u> </u><u>case</u><u>,</u>
Perimeter of the rectangle
= 2(length + width)
= 2(6.5 + 7.3)m
= 2 × 13.8 m
= <em><u>27</u></em><em><u>.</u></em><em><u>6</u></em><em><u> </u></em><em><u>m</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em><em><u>(</u></em><em><u>ii</u></em><em><u>)</u></em>
Answer:
see below
Step-by-step explanation:
