Answer:
maybe 200g
I don't know thats just a guess
HOPE ITS TURE
Aromatic side chain exhibits an electronic excited state that is closer in energy to the ground state.
- In order to respond to this query, we must decide whether a peptide bond or an aromatic side chain is demonstrating an electronic exited state that is more closely related to the ground state in terms of energy.
- When our energy is as low as possible, we are in the ground state.
- What I want to point out is that if we can choose between the two options—peptide bond or aromatic side chain—without knowing the specific reasons, we can immediately rule out two potential answers.
- Consider what we already know about energy, we have:
E = h x c/λ
- That indicates that when we have more energy, a wavelength decreases. Lower energy corresponds to higher wavelength.
- Aromatic side chains absorb between 250 and 290 nm, while peptide bonds do so between 190 and 250 nm.
- According to our breakdown, we have an electron excited state that is more closely related to the ground state in terms of energy as wavelength increases.
Thus, Aromatic side chain exhibits an electronic excited state that is closer in energy to the ground state.
To view similar questions about energy, refer to:
brainly.com/question/14483627
#SPJ4
Answer:
Temperate Grasslands
Explanation:
Tundras have nothing to do with grass. Tundras are more like ice
If It takes 60mL of 0.20M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid (
), then the concentration of the carbonic acid is 0.24M
The reaction between NaOH solution and is written below
Volume of NaOH, 
= 60 ml
Volume of , 
Molarity of , 
Molarity of NaOH, 
Number of moles of , 
Number of moles of NaOH, 
The mathematical equation for neutralization reaction is:
Substitute 
, , , = 60ml, and into the equation above in order to solve for 
Therefore, the concentration of the carbonic acid is 0.24M
Learn more here: brainly.com/question/25943090
Answer:
True
Explanation:
Step 1: Find molecular formula of sucrose
C₁₂H₂₂O₁₁
Step 2: Convert moles of oxygen present to grams
1 mol O = 16 g O
11 mol O = 176 g O
Step 3: Find molar mass of sucrose
C - 12.01 g/mol
H - 1.01 g/mol
O - 16.00 g/mol
12.01(12) + 22(1.01) + 11(16.00) = 342.34 g/mol C₁₂H₂₂O₁₁
Step 4: Set up dimensional analysis
Step 5: Multiply/Divide and cancel out units
Grams of C₁₂H₂₂O₁₁ and grams of C₁₂H₂₂O₁₁ cancel out.
We are left with grams Oxygen
176/342.34 = 0.514109 grams Oxygen
