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3 years ago

An equation _____ has one solution. 1. never 2. always 3.sometimes

Mathematics

2 answers:

Tomtit [17]3 years ago

3 0

Answer:

Option 3

Step-by-step explanation:

An equation is sometimes one solution because it can also have infinitely many solution or no solutions.

Vilka [71]3 years ago

3 0

Answer:3

An equation can have no solutions, one solution, or a bunch of solutions

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If x-2y=10 and x≠0, what is the value of 2x/y+5

VladimirAG [237]

Answer: 4

Step-by-step explanation:

x - 2y =10

x = 10 + 2y

$\frac{2x)}{y + 5}$

$\frac{2(10+2y)}{y+5}$

$\frac{20+4y}{y+5}$

$\frac{4(5+y)}{y+5}$ ... cancel like terms (y + 5)

= 4

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2 years ago

Can someone just help me out I’m bad at doing homework

jeka57 [31]

Answer:

You forgot to attach

Step-by-step explanation:

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3 years ago

A prism is a 3d shape with the same _______ all the way through

Aloiza [94]

Answer:

cross-section

Step-by-step explanation:

prism is a type of three-dimensional (3D) shape with flat sides.

It has the same cross-section all along the shape from end to end; that means if you cut through it you would see the same 2D shape as on either end.

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3 years ago

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago

Urgent Fast!!!!!!!??????

faltersainse [42]

If he has 484 plants and there are as many rows as there are plants in each row, his field is a square.

The area of a square = (side)^2

In this problem,

Area = 484

side = # of rows

Let's plug our values into the formula above

484 plants = (side)^2

Take the sqrt of both sides.

22 rows = side.

8 0

3 years ago

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