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ololo11 [35]
3 years ago
15

Estimate the measure of ∠DBC.Could someone please help me with this?

Mathematics
1 answer:
marshall27 [118]3 years ago
8 0

Answer:

Option (4). 135°

Step-by-step explanation:

From the figure attached,

Two pair of vertical angles have been given,

∠ABD and ∠CBE

∠ABE and ∠CBD

One pair of angles ∠ABD and ∠CBE are acute angles which are less than 90°.

Similarly, other pair ∠ABE and ∠DBC are obtuse angles which are more than 90°.

Therefore, out of the given options measure of one pair ∠DBC and ∠ABE should be 135°.

Option (4) will be the answer.

You might be interested in
What is the perimeter, in units, of polygon PQRSTU? Enter your answer in the box.
ololo11 [35]

Answer:

24 units

Step-by-step explanation:

Perimeter of Polygon PQRSTU = sum of all its side lengths = PQ + QR + RS + ST + TU + PU

PQ = |-4 -(-2)| = 2 units

QR = |4 - 2| = 2 units

RS = |-2 - 2| = 4 units

ST = |2 -(-2)| = 4 units

TU = |2 -(-4)| = 6 units

PU = |4 - (-2)| = 6 units

Perimeter of Polygon PQRSTU = 2 + 2 + 4 + 4 + 6 + 6 = 24 units

5 0
3 years ago
If f(1) = 2 and f(n) = f(n − 1)2 + 3 then find the value of f(3).
blondinia [14]

Answer:

52

Step-by-step explanation:

f(n) is purely based on the previous value of f(n), or f(n-1), so we can start with f(1) and work our way up. We know f(1) = 2, so to find f(2), we plug f(1) into

f(n-1)²+3 to get

f(1)²+3 = 2²+3 = 4+3=7

Thus, f(2) =7. Similarly,

f(3) = f(3-1)²+3 = f(2)² + 3 -= 7² + 3= 52

3 0
3 years ago
11+3(9-6)-4=<br> Please do it step by step.
tester [92]
11+3=14*(9-6=3)-4=38
3 0
3 years ago
Read 2 more answers
Dr. Pagels is a mammalogist who studies meadow and common voles. He frequently traps the moles and has noticed what appears to b
Alina [70]

Answer:

Null hypothesis = H₀ = There food preferences among vole species are independent of one another.

Alternate hypothesis = H₁ = There is a relationship between voles and food preference.

Expected meadow vole/apple slices = 29.983051

Expected common vole/apple slices = 28.016949

Expected meadow vole/peanut butter-oatmeal = 31.016949

Expected common vole/peanut butter-oatmeal = 28.983051

Chi-square value = χ² = 2.154239

Degree of freedom = 1

Critical value = 3.841

χ² < Critical value

We failed to reject H₀

We do not have significant evidence at the given significance level to show that there is a relationship between voles and food preference.

Step-by-step explanation:

He frequently traps the moles and has noticed what appears to be a preference for a peanut butter-oatmeal mixture by the meadow voles vs apple slices are usually used in traps, where the common voles seem to prefer the apple slices.

So he conducted a study where he used a peanut butter-oatmeal mixture in half the traps and the normal apple slices in his remaining traps to see if there was a food preference between the two different voles.

Null hypothesis = H₀ = There food preferences among vole species are independent of one another.

Alternate hypothesis = H₁ = There is a relationship between voles and food preference.

Data collected by Dr. Pagels:

                                              meadow voles     common voles      Row Total

apple slices                                     26                          32                      58

peanut butter-oatmeal                   35                          25                     60

Column Total                                   61                          57                     118

Where 118 is the grand total.

The expected number is given by

Expected = (row total)×(column total)/grand total

Expected meadow vole/apple slices = 58×61/118

Expected meadow vole/apple slices = 29.983051

Expected common vole/apple slices = 58×57/118

Expected common vole/apple slices = 28.016949

Expected meadow vole/peanut butter-oatmeal = 60×61/118

Expected meadow vole/peanut butter-oatmeal = 31.016949

Expected common vole/peanut butter-oatmeal = 60×57/118

Expected common vole/peanut butter-oatmeal = 28.983051

The chi-square statistic value is given by

χ² = Σ(Observed - Expected)²/Expected

χ² = (26 - 29.983051)²/29.983051 + (32 - 28.016949)²/28.016949 + (35 - 31.016949)²/31.016949 + (25 - 28.983051)²/28.983051

χ² = 2.154239

The degrees of freedom is given by

DoF = (row - 1)×(col - 1)

For the given case, we have 2 rows and 2 columns

DoF = (2 - 1)×(2 - 1)

DoF = 1

The given level of significance = 0.05

The critical value from the chi-square table at α = 0.05 and DoF = 1 is found to be

Critical value = 3.841

Conclusion:

Reject H₀ If χ² > Critical value

We reject the Null hypothesis If the calculated chi-square value is more than the critical value.

For the given case,

χ² < Critical value

We failed to reject H₀

We do not have significant evidence at the given significance level to show that there is a relationship between voles and food preference.

8 0
3 years ago
What is the measure of the angle formed by the minute hand and the hour hand of a clock when the clock shows 4:35? A. 72.5° B. 9
Kruka [31]
A) Minute Hand:
in 1 hour (= 60 minute) the minute hand travels 360 °
So in each minute, the minute hand travels 360/60 = 6°
And in x minute it will travel x.(6°)

B) Hour Hand:
in 1 hour (= 60 minute) the hour hand travels 360/12 = 30°
So in each minute, the hour hand will travel 30°/60° = 0.5°
And in x minute it will travel x.(0.5°)

ANGLE AT 4:35?

At 4:00, angle = 4. 30 = 120°
After 35 minutes, the minute hand strops at 35.(6°) = 210°, but during this 35 minute, the hour hand traveled 35.(0.5) = 17.5°, on top of its 120°, that makes an angle of 137.5°

So at 4:35 the angle between the hour & minute hand = 210°-137.5° =72.5°

Answer A


8 0
3 years ago
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