Answer:
false
Explanation:
you cant calculate a three variable equation knowing only one of the variables
Answer: 1) 17.65 * 10^-12 C/V; 2) 0.68 V
Explanation: In order to calculate the capacitance of one cylinder capacitor we have to use the following expression:
where and b are the inner and outer radius of teh cylinder, respectively. L is length of the cylinder.
Finally we also kwn that C=Q/ΔV
then we have
ΔV =Q/C
ΔV = 12 * 10^-12/17.65*10^-12= 0.68V
The answer is static friction. This is the friction that involves objects that do not move.
Answer:
The inside Pressure of the tank is 
Solution:
As per the question:
Volume of tank, 
The capacity of tank, 
Temperature, T' =
= 299.8 K
Temperature, T =
= 288.2 K
Now, from the eqn:
PV = nRT (1)
Volume of the gas in the container is constant.
V = V'
Similarly,
P'V' = n'RT' (2)
Also,
The amount of gas is double of the first case in the cylinder then:
n' = 2n
![\]frac{n'}{n} = 2](https://tex.z-dn.net/?f=%5C%5Dfrac%7Bn%27%7D%7Bn%7D%20%3D%202)
where
n and n' are the no. of moles
Now, from eqn (1) and (2):

