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4 years ago

Ammonia and hydrogen fluoride both have unusually high boiling points due to

Chemistry

1 answer:

nexus9112 [7]4 years ago

5 0

Answer:

C. hydrogen bonding

Explanation:

Ammonia and hydrogen fluoride are both able to exhibit hydrogen bonding due to containing nitrogen (in ammonia) and fluoride (obviously in hydrogen fluoride). Remember the unique qualities of NOF. :)

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Which of the following elements could replace copper in a single replacement reaction?

Likurg_2 [28]

I’m thinking it’s gold because lead isn’t with cooper meaning that if u switch lead with cooper it won’t work at all .

7 0

3 years ago

A certain substance has a heat of vaporization of 70.83 kJ / mol. 70.83 kJ/mol. At what Kelvin temperature will the vapor pressu

lana66690 [7]

Answer:

The answer to the question is

The temperature at which the vapor pressure will be 5.00 times higher than it was at 331 K is 353.0797 K.

Explanation:

To solve the question, we make use of the Clausius-Clapeyron equation as follows

$ln(\frac{P_2}{P_1}) = \frac{d_{vap}H}{R} (\frac{1}{T_1} -\frac{1}{T_2} )$

Where P₁ = Initial pressure

P₂ = Final pressure

T₁ = Initial temperature = 331 K

T₂ = Final temperature

dvapH = ΔvapH = Heat of vaporization = 70.83 kJ / mol.

R = Universal gas constant = 8.3145. J K⁻¹ mol⁻¹

We are required to find the temperature when P₂ = 5 × P₁

Therefore we have

$ln(\frac{5*P_1}{P_1}) = \frac{70.83}{8.3145} (\frac{1}{331} -\frac{1}{T_2} )$ = $ln(5) = 8518.853 (\frac{1}{331} -\frac{1}{T_2} )$ or T₂ = $\frac{1}{\frac{1}{331} -\frac{ln(5)}{8518.853} }$ = 353.0797 K

The vapor pressure be 5.00 times higher than it was at 331 K when the temperature is raised to 353.0797 K.

3 0

4 years ago

As a chlorine atom becomes a negative ion, the atom blanks an electron

Andrew [12]

Answer: increases by

As a chlorine atom becomes a negative ion, the atom "increases by" an electron

Explanation:

Chlorine atom has an atomic number of 17, and an electronic configuration of 1s2, 2s2 2p6, 3s2 3p5 showing 7 valence electrons in its outermost shell.

Hence, it receives a single electron to achieve a stable octet structure with electronic configuration of

1s2, 2s2 2p6, 3s2 3p6. Therefore, Cl- is a univalent negative ion with 8 valence electrons in its outermost shell. The increase is shown below

Cl + e- --> Cl-

Thus, as a chlorine atom becomes a negative ion, the atom "increases by" an electron

7 0

3 years ago

Which is an endothermic process?

natita [175]

Answer: Option (d) is the correct answer.

Explanation:

Endothermic process is a process in which energy or heat is absorbed by reactant species.

For example, melting of ice cubes is an endothermic process as it is absorbing heat from the surrounding and gives a cooling effect.

Thus, we can conclude that the process in which a substance gains energy is an endothermic process.

4 0

4 years ago

Read 2 more answers

Will a precipitate (ppt) form when 20.0 mL of 1.1 × 10 –3 M Ba(NO 3) 2 are added to 80.0 mL of 8.4 × 10 –4 M Na 2CO 3?

erastova [34]

Answer:

A precipitate will form, BaCO₃

Explanation:

When Ba²⁺ and CO₃²⁻ ions are in an aqueous media, BaCO₃(s), a precipitate, is produced following its Ksp expression:

Ksp = 5.1x10⁻⁹ = [Ba²⁺] [CO₃²⁻]

Where the concentrations of the ions are the concentrations in equilibrium

For actual concentrations of a solution, you can define Q, reaction quotient, as:

Q = [Ba²⁺] [CO₃²⁻]

If Q > Ksp, the ions will react producing BaCO₃, if not, no precipitate will form.

Actual concentrations of Ba²⁺ and CO₃²⁻ are:

[Ba²⁺] = [Ba(NO₃)₂] = 1.1x10⁻³ × (20.0mL / 100.0mL) = 2.2x10⁻⁴M

[CO₃²⁻] = [Na₂CO₃] = 8.4x10⁻⁴ × (80.0mL / 100.0mL) = 6.72x10⁻⁴M

100.0mL is the volume of the mixture of the solutions

Replacing in Q expression:

Q = [Ba²⁺] [CO₃²⁻]

Q = [2.2x10⁻⁴M] [6.72x10⁻⁴M]

Q = 1.5x10⁻⁷

As Q > Ksp

<h3>A precipitate will form, BaCO₃</h3>

8 0

3 years ago