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weqwewe [10]
3 years ago
13

Ammonia and hydrogen fluoride both have unusually high boiling points due to

Chemistry
1 answer:
nexus9112 [7]3 years ago
5 0

Answer:

C. hydrogen bonding

Explanation:

Ammonia and hydrogen fluoride are both able to exhibit hydrogen bonding due to containing nitrogen (in ammonia) and fluoride (obviously in hydrogen fluoride). Remember the unique qualities of NOF. :)

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A neutral atom in the ground state of Sulfur has its outer most valence electron in which orbital? f d
Natasha_Volkova [10]

<u>Answer:</u> The outermost valence electron enters the p orbital.

<u>Explanation:</u>

Valence electrons are defined as the electrons which are present in outer most orbital of an atom.

Sulfur is the 16th element of the periodic table having 16 electrons.

Electronic configuration of sulfur atom is 1s^22s^22p^63s^23p^4

The number of valence electrons are 2 + 4 = 6

These 6 electrons enter s-orbital and p-orbital but the outermost valence electron will enter the p-orbital.

Hence, the outermost valence electron enters p orbital.

3 0
3 years ago
About how many elements are found on the periodic table? Question 8 options:
krek1111 [17]

the answer is actually 118 look it up

3 0
3 years ago
Calculate AH for the reaction:<br> 2N2 (g) + 6H20 (g) → 302 (g) + 4NH3(g)
Ratling [72]

Answer:

Explanation:

4NH₃ (g) + 3O₂ (g) ⇒ 2N₂ (g) + 6H₂ O(1)

ΔH_r={\sum}{ \Delta }H_f(\text{product})-{\sum}{ \Delta }H_f(\text{reactant})

ΔH r =(2ΔH f(N 2 )+6ΔH f (H 2 O(l)))−(4ΔH f​ (NH 3 (g))+3ΔH f (O 2 (g)))

ΔH rex =[2×0+6×(−286)]−[4×(−46)+3×0]=−1716+186

ΔH rex =−1532kJ/mol

Thermodynamics is a branch of physical chemistry that studies heat and its effects and interactions. Governed by the four main laws, thermodynamics plays a huge role in physics and chemistry, and is also responsible for the law of conservation of energy, a fundamental rule in science.

7 0
1 year ago
a sample of ammonia contains 9g hydrogen and 42g nitrogen. another sample contains 5g hydrogen .calculate the amount of nitrogen
balandron [24]
9 g of hydrogen - 42 g of nitrogen
5 g of hydrogen - x g of nitrogen

9x=42 \cdot 5 \\&#10;9x=210 \\&#10;x \approx 23.33

The mass of nitrogen in the second sample is 23.33 g.
4 0
3 years ago
Can anyone please help?
Marrrta [24]

is it me bc i cant even see the page:?

5 0
3 years ago
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