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Tanya [424]
3 years ago
11

What is the pH of an aqueous solution that has a hydroxide ion concentration of 1.0 x 10^-5 M?​

Chemistry
1 answer:
Alona [7]3 years ago
8 0

Answer:

pH = 9

Explanation:

pOH = -log[OH-] = -log(1.0 x10^-5) = 5

pOH + pH = 14

pH = 14 - 5 = 9

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KonstantinChe [14]
It has potential energy.
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What are the things to be considered in feeding of poultry birds ?​
tamaranim1 [39]

Answer:

Poultry feed contains many ingredients including:

grains (e.g. wheat, barley, sorghum)

protein meals (soybean meal, canola meal, animal protein meals)

fats and oils.

amino acids.

vitamins and minerals

Explanation:

4 0
3 years ago
Jason combines the two intermediate steps shown.
Snowcat [4.5K]

Answer:

Place two of them as reactants.

Explanation:

  • We have the two steps of reactions:

1) N₂(g ) + O₂(g) → 2NO(g).

2) 2NO(g )+ O₂(g) → 2NO₂(g).

  • Adding the two equation with cancelling the intermediate (NO), we get:

<em>N₂(g ) + 2O₂(g) → 2NO₂(g).</em>

<em></em>

NO is cancelled out because there is one in each equation in the products side in eq. 1 and in oriduct side in eq. 2.

<em>So, we place two of oxygen as reactants.</em>

7 0
3 years ago
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Pleaseeeeeee hlepThe half-life of cobalt-60 is 5.26 years. After 10.52 years, 5 grams of a 20-gram sample will remain.
vladimir1956 [14]

The half-life of cobalt-60 is 5.26 years. After 10.52 years, 5 grams of a 20-gram sample will remain is TRUE

<u>Explanation:</u>

Mass of cobalt = 20 g  

Half-life = 5.26 years  

Mass remains after 10.52 years = 5 g  

This can be solved by using given below formula, m(t)=m_{o}\left(\frac{1}{2}\right)^{\frac{l}{5.26}}

m_{0} = initial mass  

t = number of years from when the mass was m_0  

m(t) = remaining mass after t years  

Number of half-lives = \frac{\text { Time elapsed }}{\text { Half -life }}

Number of half-lives = \frac{10.52 \text { years }}{5.26 \text { years }}

Number of half-lives = 2  

At time zero = 20 g  

At first half-life = \frac{20\ g}{2}  = 10 g  

At second half life = \frac{10\g}{2} = 5 g  

The given statement is true.

4 0
3 years ago
If 2.0 g of copper(II) chloride react with excess sodium nitrate, what mass of sodium chloride is formed in this double replacem
cluponka [151]

Taking into account the reaction stoichiometry, 1.729 grams of NaCl is formed.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CuCl₂ + 2 NaNO₃ → Cu(NO₃)₂ + 2 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CuCl₂: 1 mole
  • NaNO₃: 2 moles
  • Cu(NO₃)₂ : 1 mole
  • NaCl: 2 moles

The molar mass of the compounds is:

  • CuCl₂: 134.44 g/mole
  • NaNO₃: 85 g/mole
  • Cu(NO₃)₂ : 187.54 g/mole
  • NaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • CuCl₂: 1 mole ×134.44 g/mole= 134.44 grams
  • NaNO₃: 2 moles ×85 g/mole= 170 grams
  • Cu(NO₃)₂ : 1 mole ×187.54 g/mole= 187.54 grams
  • NaCl: 2 moles ×58.45 g/mole= 116.9 grams

<h3>Mass of NaCl formed</h3>

The following rule of three can be applied: If by stoichiometry of the reaction 134.44 grams of CuCl₂ form 116.9 grams of NaCl, 2 grams of CuCl₂ form how much mass of NaCl?

mass of NaCl=\frac{2 grams of CuCl_{2}x116.9 grams of NaCl }{134.44grams of CuCl_{2}}

<u><em>mass of NaCl= 1.739 grams</em></u>

Finally, 1.729 grams of NaCl is formed.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

6 0
2 years ago
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