Answer:
73325J
Explanation:
Given parameters:
Mass of water = 0.5kg
Initial temperature = 30°C
Final temperature = 65°C
Specific heat capacity = 4190J/kg°C
Unknown:
Amount of energy absorbed = ?
Solution:
The amount of energy absorbed can be derived using the expression below;
H = m c Δt
H is the amount of energy
m is the mass
c is the specific heat
Δt is the change in temperature
H = 0.5 x 4190 x (65 - 30 )
H = 73325J
Answer:
2N
Explanation:
subtract rthe two forces to see which is greater
4-2=2
part 1
mass = ρ x V
mass = 1739 kg/m³ x 3.8 km³ = 6608.2 kg
PE (potential energy)= mgh
PE = 6608.2 kg x 9.81 x 403
PE = 2.61 x 10⁷ J
part 2
megaton of TNT (Mt) =4.2 x 10¹⁵ J
convert PE to Mt:
2.61 x 10⁷ J : 4.2 x 10¹⁵ J = 6.21 x 10⁻⁹ Mt
