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anygoal [31]
3 years ago
5

One piece of copper jewelry at 111°C has exactly twice the mass of another piece, which is at 28°C. Both pieces are placed insid

e a calorimeter whose heat capacity is negligible. What is the final temperature inside the calorimeter (c of copper = 0.387 J/g·K)?
Physics
1 answer:
vladimir2022 [97]3 years ago
3 0

Answer:

83.33 C

Explanation:

T1 = 111 C, m1 = 2m

T2 = 28 C, m2 = m

c  = 0.387 J/gK

Let the final temperature inside the calorimeter of T.

Use the principle of calorimetery

heat lost by hot body = heat gained by cold body

m1 x c x (T1 - T) = m2 x c x (T - T2)

2m x c X (111 - T) = m x c x (T - 28)

2 (111 - T) = (T - 28)

222 - 2T = T - 28

3T = 250

T = 83.33 C

Thus, the final temperature inside calorimeter is 83.33 C.

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Answer: (C) The ball will accelerate to about 20 m/s.

Explanation: The ball is in free fall and no other but gravitational force acts on it. This means the ball will be subject to the gravitational acceleration, which is about 9.8 m/s^2. So after one additional second the ball will increase its velocity to (10+9.8) m/s = 19.8 m/s or approx. 20 m/s.

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3 years ago
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Two rowers, who can row at the same speed in still water, head across a river. . . The first rower (Alice) heads straight across
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"Alice" is the one among the following choices given in the question that arrives at the other side first. the correct option among all the options that are given in the question is the first option or option "A". the other choices can be easily neglected. i hope that this is the answer that has come to your great help.
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3 years ago
A 200N force pushes forward on the 20kg truck. The truck pulls two crates connected together by ropes, as shown. The gravitation
devlian [24]

Force on left crate, right crate and truck we need to draw here

First we will write the equation for left crate

T_{left} = m*a

T_{left} = 20*a

Now similarly for right crate

T_{right} - T_{left} = 20*a

now for truck

F - T_{right} = 20*a

Now we know that F = 200 N

200 - T_{right} = 20*a

now add all three equation

T_{left} + T_{right} - T_{left} + 200 - T{right} = 20a + 20 a + 20a

200 = 60 a

a = 10/3 m/s^2

now we will find all tension using this value of acceleration

T_{left} = 20 * \frac{10}{3} = \frac{200}{3} N

T_{right} - \frac{200}{3} = 20*\frac{10}{3}

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6 0
3 years ago
What is the magnitude of the electric field at the point if the electric potential in the region is given by V 2.00xyz2, where V
Hatshy [7]

Answer:

Electric field at a point ( x , y , z) is E=-2yz^2-2xz^2-4xyz .

Explanation:

Given :

Electric potential in the region is , V = 2xyz^2\ .

We need to find the electric field .

We know , electric field , E=-\dfrac{dV}{dr}  { Here r is distance }

In coordinate system ,

E=-\dfrac{dV}{\delta x }-\dfrac{dV}{\delta y }-\dfrac{dV}{\delta z }  { \delta is partial derivative }

Putting all values we get ,

E=-\dfrac{2xyz^2}{\delta x }-\dfrac{2xyz^2}{\delta y }-\dfrac{2xyz^2}{\delta z }\\\\E=-2yz^2-2xz^2-4xyz

Hence , this is the required solution.

3 0
3 years ago
A toy car has an initial acceleration of 2 m/s" across a horizontal surface after it is released from rest. After the car travel
Ganezh [65]

Answer:

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t is the time taken to travel that distance

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a is the acceleration of that system

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