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anygoal [31]
3 years ago
5

One piece of copper jewelry at 111°C has exactly twice the mass of another piece, which is at 28°C. Both pieces are placed insid

e a calorimeter whose heat capacity is negligible. What is the final temperature inside the calorimeter (c of copper = 0.387 J/g·K)?
Physics
1 answer:
vladimir2022 [97]3 years ago
3 0

Answer:

83.33 C

Explanation:

T1 = 111 C, m1 = 2m

T2 = 28 C, m2 = m

c  = 0.387 J/gK

Let the final temperature inside the calorimeter of T.

Use the principle of calorimetery

heat lost by hot body = heat gained by cold body

m1 x c x (T1 - T) = m2 x c x (T - T2)

2m x c X (111 - T) = m x c x (T - 28)

2 (111 - T) = (T - 28)

222 - 2T = T - 28

3T = 250

T = 83.33 C

Thus, the final temperature inside calorimeter is 83.33 C.

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aivan3 [116]
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6 0
4 years ago
|| Suppose a plane accelerates from rest for 30 s, achieving a takeoff speed of 80 m/s after traveling a distance of 1200 m down
rjkz [21]

Answer:

600 m is required for smaller plane to reach its takeoff speed.

Explanation:

We have equation of motion  

          80 = 0 + a x 30

          a = 2.67 m/s²

Now finding distance traveled by second flight

       v² = u²+2as

      40² = 0²+2 x 2.67 x s

       s = 300 m

So 300 m is required for smaller plane to reach its takeoff speed.

7 0
4 years ago
Sami pops a helium balloon at a birthday party. What will happen to the particles of helium that were in the balloon?
Anit [1.1K]

They will mix with air. Air consists mostly of nitrogen and oxygen but there are also traces of CO2 and noble gases in air, and helium is one of those noble gases.

4 0
3 years ago
Need help on this on 6 and 7
Paladinen [302]
6) the last one
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7 0
4 years ago
A charge +q is located at the origin, while an identical charge is located on the x axis at x = +0.57 m. A third charge of +2q i
Jlenok [28]

Answer:

The third charge placed is 0.80 m.

Explanation:

Given that,

Distance = 0.57 m

First charge = q

Third charge = 2q

We need to calculate the electrostatic force on charge q₁ due to q₂

Using formula of electrostatic force

F_{21}=\dfrac{kq_{1}q_{2}}{r_{1}^2}

When placed another charge q₃ at certain distance from origin, then the net force on charge q₁ due to both charges is

F_{net}=F_{21}+F_{31}

The net electrostatic force on the charge at the origin doubles.

2F_{21}=F_{21}+F_{31}

F_{31}=F_{21}

\dfrac{kq_{3}q_{1}}{r_{2}^2}=\dfrac{kq_{2}q_{1}}{r_{1}^2}

\dfrac{q_{3}}{r_{2}^2}=\dfrac{q_{2}}{r_{1}^2}

r_{2}^2=\dfrac{q_{3}}{q_{2}\timesr_{1}^2}

r_{2}=\sqrt{\dfrac{q_{3}}{q_{2}}}r_{1}

Put the value into the formula

r_{2}=\sqrt{\dfrac{2q}{q}}\times0.57

r_{2}=\sqrt{2}\times0.57

r_{2}=0.80\ m

Hence, The third charge placed is 0.80 m from origin in x-axis.

4 0
3 years ago
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