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3 years ago

What’s the answer need help

Mathematics

1 answer:

e-lub [12.9K]3 years ago

5 0

Answer:

D. last option

Step-by-step explanation:

distribute the exponents outside of parentheses to terms in side to get

x^10 y^20 z^5 on top

and x^2 y^2

then you can subtract the exponents of like terms from numerator and denominator to get

x^8 y^18 z^5

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NEED HELP WITH THESE QUESTIONS

amm1812

For this case we must solve the following questions:

Question 1:

We should simplify the following expression:

$\frac {\frac {m ^ 2 * n ^ 3} {p ^ 3}} {\frac {mp} {n ^ 2}} =$

Applying double C we have:

$\frac {m ^ 2 * n ^ 3 * n ^ 2} {mp * p ^ 3} =$

By definition of multiplication of powers of the same base we have to place the same base and add the exponents: $\frac {m ^ 2 * n ^ 5} {m * p ^ 4} =$

Canceling common terms:

$\frac {mn ^ 5} {p ^ 4}$

Answer:

Option A

Question 2:

We should simplify the following expression:

$\frac {3xyz ^ 2} {6y ^ 4} * \frac {2y} {xz ^ 4}$

So, we have:

$\frac {3xyz ^ 2 * 2y} {6y ^ 4 * xz ^ 4} =\\\frac {6xy ^ 2z ^ 2} {6y ^ 4xz ^ 4} =$

Simplifying common terms:

$\frac {1} {y ^ 2z ^ 2}$

Answer:

Option D

Question 3:

We factor the following expressions to rewrite the experience:

$r ^ 2 + 7r + 10$ : We look for two numbers that multiplied give 10 and added 7:

$(r + 5) (r + 2)$

$r ^ 2-5r-50:$ We look for two numbers that multiplied give -50 and added -5:

$(r-10) (r + 5)$

$3r-30 = 3 (r-10)$

Rewriting the given expression we have:

$\frac {(r + 5) (r + 2) * 3 (r-10)} {3 (r-10) (r + 5)} =$

We simplify common terms in the numerator and denominator we have:

$(r + 2)$

Answer:

Option D

4 0

3 years ago

Read 2 more answers

Arun took a taxi from his house to the airport. The taxi company charged a pick-up fee of $4 plus $4.25 per mile. The total fare

Natasha2012 [34]

Here we must write and solve a linear equation to find the number of miles that Arun traveled in the taxi. We will find that Eva traveled 11 miles.

So we know that the taxi charges a fee of $4.10 and then a plus of $0.50 per mile.

So if you travel for m miles, the cost equation is:

C(m) = $4.10 + $0.50*m

Now, we know that for Eva the total fare (total cost) was $9.60, then we need to solve:

$9.60 = C(m) = $4.10 + $0.50*m

$9.60 = $4.10 + $0.50*m

$9.60 - $4.10 = $0.50*m

$5.50 = $0.50*m

$5.50/$0.50 = m = 11

This means that Arun traveled 11 miles in the taxi.

5 0

2 years ago

Simplify the following expression and write in standard form: 3 x (6y - 4y + 5x) PLEASE HELP

mylen [45]

Answer: 15x^2+6xy

Step-by-step explanation: 3x(6y−4y+5x)

(3x)(6y+−4y+5x)

(3x)(6y)+(3x)(−4y)+(3x)(5x)

18xy−12xy+15x^2

15x^2+6xy

8 0

3 years ago

10a3 what is the vocabulary for 10

dangina [55]

Answer:

Coefficient

Step-by-step explanation:

If it is 10a^3 (10 times the variable "a" cubed), then 10 is the coefficient.

3 0

3 years ago

A whole number is 6 more than 2 times another number. The sum of the two numbers is less than 50. This can be written in an ineq

alukav5142 [94]

Answer:

13, 14

Step-by-step explanation:

The parameters of the numbers are;

A whole number value = 2 × Another number + 6

The sum of the two numbers is less than 50

Given that the first number is equal to more than twice the second number, we have that the first number is the larger number, while the second number is the smaller number

Where 'x' represents the second number, we get;

x + 2·x + 6 < 50

Simplifying gives;

3·x + 6 < 50

x < (50 - 6)/3 = 14. $\overline 6$

x < 14. $\overline 6$

Therefore, the numbers for which the inequality holds true are numbers less than 14. $\overline 6$ . From the given option, the numbers are 13, and 14.

3 0

3 years ago