The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
Read more on average of integers;
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The Answer is in the attached file, I'm sorry if I can't write it on laptop, hope this helps man! :) and tell me if it's correct or wrong when your teacher see's it.
Answer:
60
Step-by-step explanation:
The least common multiple of 2 and 20 is 20.
The only factor that is shared with 20 and 3 is 1. Therefore, the least common multiple will have to be 20*3, which is 60.
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16.666666666667%
How much is 10 out of 60 written as a percentage? Convert fraction (ratio) 10 / 60 Answer: 16.666666666667%
