The current passing through a circuit consisting of a battery of 12 V and resistor of 2 ohms is 6 Ampere
.
Explanation:
- Assume the wires are ideal with zero resistance.
- The current passing through the circuit will be
I = V/R = 12/2 = 6.000 A.
Answer:
16.7 mF
Explanation:
The total capacitance of two capacitors connected in series is given by the formula:

in our problem, we have:
C1 = 45 mF is the capacitance of the first capacitor
C2 = 26 mF is the capacitance of the second capacitor
Substituting into the equation, we find:
