Consider that when heigt is 35 meters, the velocity is zero. The you can use the formula for free fall with initial velocity zero

Vf = √(2gh) = √(2*9.8m/s^2 * 35m) = √686m^2/s^2 = 26.2 m/s

Assumption: 35 m is the maximum height from the ground, else, if the maximum heigth from the ground is 35 m + 1 m = 36 m, the numbers are:

Vf = √(2*9.8m/s^2*36m) = 26.6 m/s

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3 years ago

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Two electric charges, held a distance, dd, apart experience an electric force of magnitude, FF, between them. If one of the char

lorasvet [3.4K]

Answer:

$F'=2F$

Explanation:

The Coulomb's law states that the magnitude of the electrostatic force between two charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them:

$F=\frac{kq_1q_2}{d^2}$

In this case, we have $q_1'=2q_1$ :

$F'=\frac{kq'_1q_2}{d^2}\\F'=\frac{k(2q_1)q_2}{d^2}\\F'=2\frac{kq_1q_2}{d^2}\\F'=2F$

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3 years ago