What are the two outcomes for a proto star?

Tether ball is a game children play in which a ball hangs from a rope attached to the top of a tall pole. The children hit the b

Murljashka [212]

Answer:

a_total = 14.022 m/s²

Explanation:

The total acceleration of a uniform circular motion is given by the following formula:

$a=\sqrt{a_c^2+a_T^2}$ (1)

ac: centripetal acceleration

aT: tangential acceleration

Then, you first calculate the centripetal acceleration by using the following formula:

$a_c=r\omega^2$

r: radius of the circular trajectory = 2.0m

w: final angular velocity of the ball = 7.0 rad/s

$a_c=(2.0m)(7.0rad/s)^2=14.0\frac{m}{s^2}$

Next, you calculate the tangential acceleration. aT is calculate by using:

$a_T=r\alpha$ (2)

α: angular acceleration

The angular acceleration is:

$\alpha=\frac{\omega_o-\omega}{t}$

wo: initial angular velocity = 13 rad/s

t: time = 15 s

Then, you use the expression for the angular acceleration in the equation (1) and solve for aT:

$a_T=r(\frac{\omega_o-\omega}{t})=(2.0m)(\frac{7.0rad/s-13.0rad/s}{15s})=-0.8\frac{m}{s^2}$

Finally, you replace the values of aT and ac in the equation (1), in order to calculate the total acceleration:

$a=\sqrt{(14.0m/s^2)^2+(-0.8m/^2)^2}=14.022\frac{m}{s^2}$

The total acceleration of the ball is 14.022 m/s²

5 0

3 years ago

A meter stick is balanced at the 50 cm mark. You tie 70 N weight at the 30 cm mark. What weight at the 90 cm mark would create a

sveticcg [70]

70x(50-30) = W x (90-50)
1400 = W x 40
W = 35N

5 0

3 years ago

A Star's Apparent magnitude is a measure of

iren [92.7K]

Answer:

C. How bright it seems to us

Explanation:

4 0

4 years ago

The titanium shell of an SR-71 airplane would expand when flying at a speed exceeding 3 times the speed of sound. If the skin of

Fed [463]

Answer:

The 10-meter long rod of an SR-71 airplane expands 0.02 meters (2 centimeters) when plane flies at 3 times the speed of sound.

Explanation:

From Physics we get that expansion of the rod portion is found by this formula:

$\Delta l = \alpha\cdot l_{o}\cdot (T_{f}-T_{o})$ (Eq. 1)

Where:

$\Delta l$ - Expansion of the rod portion, measured in meters.

$\alpha$ - Linear coefficient of expansion for titanium, measured in $\frac{1}{^{\circ}C}$ .

$l_{o}$ - Initial length of the rod portion, measured in meters.

$T_{o}$ - Initial temperature of the rod portion, measured in Celsius.

$T_{f}$ - Final temperature of the rod portion, measured in Celsius.

If we know that $\alpha = 5\times 10^{-6}\,\frac{1}{^{\circ}C}$ , $l_{o} = 10\,m$ , $T_{o} = 0\,^{\circ}C$ and $T_{f} = 400\,^{\circ}C$ , the expansion experimented by the rod portion is:

$\Delta l = \left(5\times 10^{-6}\,\frac{1}{^{\circ}C} \right)\cdot (10\,m)\cdot (400\,^{\circ}C-0\,^{\circ}C)$

$\Delta l = 0.02\,m$

The 10-meter long rod of an SR-71 airplane expands 0.02 meters (2 centimeters) when plane flies at 3 times the speed of sound.

4 0

3 years ago

A piano string having a mass per unit length equal to 5.00× 10⁻³kg / m is under a tension of 1350N . Find the speed with which a

DiKsa [7]

Based on the mass per unit length and the tension, the speed that the wave travels on this string is 519.615 m/s.

<h3>What is the speed?</h3><h3 />

The speed that the wave travels can be found as:

Velocity² = Tension / Mass per length

Solving gives:

Velocity² = 1,350 / 0.005

Velocity² = 270,000

Velocity = √270,000

= 519.615 m/s

Find out more on the speed of a wave at brainly.com/question/12215474

#SPJ4

8 0

2 years ago