So what this is is
many words
assuming year 0 is 2017
so compound first thing till 2020, take out 30000
the remaining is copmpounded til 2022, take out 50000
remaining is compounded for 1 more year and that is equal to 80000
so from 2017 to 2020, that is 5 years
from 2020 to 2022 is 2 years
from 2022 to 2023 is 1 year
work backwards
A=P(r+1)^t
last one
A=80000
P=?
r=0.08
t=1 year
80000=P(1.08)^1
divide both sides by 1.08
I would leave in fraction
20000000/27=P
now that is the remaining after paying 50000, after 2 years of compounding
so
50000+(2000000/27)=P(1.08)^2
solve using math
about
106374=P
now reverse back
5 years
paid 30000
30000+106374=P(1.08)^5
solve using math
92813.526=P
round
$92813.53
put $92813.53 in the fund
Answer:
Step-by-step explanation:
f=v+at
It requires you to make a the subject of the formula
f-v=at
Dividing both sides by t then
Therefore, the equivalent for a is
Another effective strategy for helping students improve their mathematics performance is related to solving word problems. More specifically, it involves teaching students how to identify word problem types based on a given problem’s underlying structure, or schema. Before learning about this strategy, however, it is helpful to understand why many students struggle with word problems in the first place.
Difficulty with Word Problems
Most students, especially those with mathematics difficulties and disabilities, have trouble solving word problems. This is in large part because word problems require students to:
Answer: −5.6x −7
Step-by-step explanation:
9514 1404 393
Answer:
$2400
Step-by-step explanation:
The question is asking the amount invested in fund B. We can let 'b' represent that amount. Then the amount invested in fund A is (6000-b). The total profit from the investments is ...
0.02(6000 -b) +0.07(b) = 0.04(6000)
120 +0.05b = 240 . . . . . simplify
0.05b = 120 . . . . . . . . . subtract 120
b = 2400 . . . . . . . . . . .divide by 0.05
Alonzo invested $2400 in fund B.
