The solubility Barium chromate in grams per liter = 2.78 . 10⁻³ grams/L
359 liters of water are required to dissolve 1.00 g of Barium chromate
<h3>Further explanation </h3>Solubility is the maximum amount of a substance that can dissolve in some solvents. Factors that affect solubility
Ksp is an ion product in equilibrium
Solubility relationships and solubility constants (Ksp) of the AxBa solution can be stated as follows.
AₓBₐ (s) ← ⎯⎯⎯⎯ → x Aᵃ⁺ (aq) + a Bˣ⁻ (aq)
s xs as
Ksp = [Aᵃ⁺] ˣ [Bˣ⁻] ᵃ
Ksp = (xs) ˣ (as) ᵃ
Solubility units in the form of mol / liter or gram / liter
At 25.°C, the molar solubility of Barium chromate BaCrO₄ in water is 1.10. 10⁻⁵M.
to change units to grams / liter, we multiply by molar mass:
M BaCrO₄ = Ba + Cr + 4. Ar O
M BaCrO₄ = 137 + 52 + 4.16
M BaCrO₄ = 253
So the solubility is in grams / liter
= 1.10 . 10⁻⁵ mol / liter x 253 grams / mol
= 278.3 .10⁻⁵ = 2.78 . 10⁻³ grams/L
(3 significant numbers, 2.7 and 8)
If we dissolve 1 gram of Barium chromate into the solution, we need water :
= 1 grams / 2.78 . 10⁻³ grams / liter
= 359 liters
(3 significant numbers, 3.5 and 9)
<h3>Learn more </h3>
the rate of solubility
influencing factors are both solubility and the rate of dissolution
The solubility of a substance
Keywords: solubility, silver chromate, a significant number
Answer: 7.79 grams of ethanol were put into the beaker.
Explanation:
To calculate the mass of ethanol, we use the equation:
Density of ethanol = 0.779 g/mL
Volume of water = 10.00 mL
Putting values in above equation, we get:
Thus 7.79 grams of ethanol were put into the beaker.