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VLD [36.1K]
2 years ago
12

In the chemical equation 4Fe + 3O2 → 2Fe2O3, 20.99 grams of iron (Fe) are needed to produce 30.01 g of Fe2O3.

Chemistry
1 answer:
muminat2 years ago
4 0
Well, let’s use stoichiometry to find out.
30.01g Fe2O3 x (1molFe203/159.69gFeNo3)
* (4molFe/2molFeNO3) x (55.845gFe/1molFe) = 20.99 g Fe needed to produce 30.01g of Fe2O3
So, this is true!

Confused where I got the values from?
- the 30.01g Fe2O3 comes from the problem.
- the 159.69g Fe2NO3 is the molar mass found by added the mass of each element and how much of each element is present.
-the 4mol of Fe and the 2mol Fe2NO3 are found in the balanced equation.
-the 55.845 g of Fe is the molar mass of fe on the periodic table.
hope this helps!
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    1)            <u>  35.94  </u>    =1.33111                     <u>  64.06 </u>     = 2.001875

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    2)          =    <u> 1.33111 </u>                                 = <u>  2.001875  </u>

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1) Divide the percentage given in question by the Relative Atomic Mass (RAM)

of the given elements.

2) When you find the answers of the first part of question, divide these once again but this time, by the lowest number you found in part 1.

3) and 4) Write down the values. If you get a decimal which is in between 0.3-0.7 (including the 0.3 and 0.7), you cannot make it a whole number by rounding of. Therefore, multiply the decimal with a whole number until you get a whole number as your answer. In this question, when you multiply 1.5 by 2, the answer is 3 which is a whole number. Multiply the other whole number by the same number as that you multiplied for 1.5. And use these numbers in part 4 to make the empirical formula which is Aluminium Sulfide (Al2S3)

Hope this helps you :)))

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