Question

In the chemical equation 4Fe + 3O2 → 2Fe2O3, 20.99 grams of iron (Fe) are needed to produce 30.01 g of Fe2O3.

Answer 1

Well, let’s use stoichiometry to find out.
30.01g Fe2O3 x (1molFe203/159.69gFeNo3)
* (4molFe/2molFeNO3) x (55.845gFe/1molFe) = 20.99 g Fe needed to produce 30.01g of Fe2O3
So, this is true!

Confused where I got the values from?
- the 30.01g Fe2O3 comes from the problem.
- the 159.69g Fe2NO3 is the molar mass found by added the mass of each element and how much of each element is present.
-the 4mol of Fe and the 2mol Fe2NO3 are found in the balanced equation.
-the 55.845 g of Fe is the molar mass of fe on the periodic table.
hope this helps!