Answer:
a) Ba(NO₃)₂(aq) + (NH₄)₂SO₄(aq) ⇒ 2 NH₄NO₃(aq) + BaSO₄(s)
b) CoCl₃(aq) + 3 NaOH(aq) ⇒ 3 NaCl(aq) + Co(OH)₃(s)
c) 2 FeCl₃(aq) + 3 (NH₄)₂S(aq) ⇒ 6 NH₄Cl(aq) + Fe₂S₃(s)
Explanation:
We have 3 double displacement reactions, in which both reactants exchange their cations and anions, and an insoluble compound is formed and precipitates as a solid. This is indicated as (s).
a) Ba(NO₃)₂(aq) + (NH₄)₂SO₄(aq) ⇒ 2 NH₄NO₃(aq) + BaSO₄(s)
b) CoCl₃(aq) + 3 NaOH(aq) ⇒ 3 NaCl(aq) + Co(OH)₃(s)
c) 2 FeCl₃(aq) + 3 (NH₄)₂S(aq) ⇒ 6 NH₄Cl(aq) + Fe₂S₃(s)
19. For the reaction, 2S+ 30=2SO3, how many moles of so3 will be produced from 12.5 g 02 and excess S?
:
For the reaction: 2S(s) + 3O2 -> 2SO2(g) How many moles of SO3 will be produced from 2.0 mol O2 and excess S?
The activity series goes top to bottom, most active to least active elements, going: Li, K, Ba, Sr, Ca, Na, Mg, Mn, Zn, Fe, Cd, Co, Ni, Sn, Pb, H, Cu, Ag, Hg, Au.
Thus, your list of metals would go from most reactive to least reactive: Li, K, Mg, Zn, Fe, Cu, Au
