The correct answer is A. Charging by friction
Explanation
When someone rubs a comb with their hair when they are combing it and the hair sticks to the comb occurs a phenomenon called electrization, in which a neutral body becomes charged or loses an electrical charge (electrons). One way that electrization occurs is through the rubbing of two neutral bodies which causes one to be positively charged and the other negatively causing them to attract each other by magnetism. Therefore, the correct answer is A. Charging by friction
The human body has 23 pairs of chromosomes or 46 chromosomes in total that make up our traits and DNA
<span>M(NO</span>₃<span>)</span>₂<span> fully separates into M</span>²⁺<span> and NO</span>₃<span> </span>²⁻<span> </span><span>and M(OH)</span>₂<span> partially separates
as <span>M</span></span>²⁺<span><span> and 2OH</span></span>⁻
<span>M(NO</span>₃<span>)</span>₂<span><span> </span>→
M</span>²⁺<span> + 2NO</span>₃²⁻
<span>0.202 M 0.202 M</span>
<span> M(OH)</span>₂<span>(s) ↔ <span>M</span></span>²⁺<span><span> (aq) + 2OH</span></span>⁻<span><span>(aq)</span></span>
<span>I - -</span>
<span>C -X +X +2X</span>
<span>E X 2X</span>
<span>Ksp = [M</span>²⁺<span> (aq)] [OH</span>⁻<span>(aq)]</span>²
4.45 * 10∧-12 = (0.202
+ X ) (2X)²
Since X is very small, (0.202 + X ) = 0.202
<span>4.45 * 10<span>-12 </span>= 0.202 *
4X</span>²
<span> X = 2.347 </span>× 10∧-6 M
Hence
the solubility of <span>M(OH)2
is 2.347 </span>× 10∧-6 M
Soil is built up of clastic particles, organics, and clay while sand is a combination of rocks, minerals, and fragments of rotting shells.
Soil particles are larger in size and mass together, Sand particles are tinier and individual.
<u>Explanation:</u>
So, the soil is weaker than sand particles. When we mix soil and sand into the water, we acknowledge that soil particles somewhat settle at the bottom while designing parts mixed into water. Sand is almost heavier than water so it settles down at the base.
Soil particles settle faster and will be on the bottom while the sand particles will be on top. And no this is not a great method to define particle size distribution.
Answer: an alpha particle/alpha emission
Explanation: