Answer : The enthalpy change for the solution is 166.34 kJ/mol
Explanation :
First we have to calculate the enthalpy change of the reaction.
Formula used :
where,
= change in enthalpy = ?
C = heat capacity of water =
m = total mass of sample = 2.174 + 127.4 = 129.6 g
= initial temperature =
= final temperature =
Now put all the given values in the above expression, we get:
Now we have to calculate the moles of AX added to water.
Now we have to calculate the enthalpy change for the solution.
As, 0.04592 moles releases heat = 7638.36 J
So, 1 moles releases heat =
Therefore, the enthalpy change for the solution is 166.34 kJ/mol
In most cases, carbon shares electrons with other atoms (usual valence of 4). This is because carbon typically bonds with elements which have a similar electronegativity. Examples of covalent bonds formed by carbon include carbon-carbon, carbon-hydrogen, and carbon-oxygen bonds
Answer:
A chemical reaction is a process in which the chemical bonds of a substance are broken or rearranged. One or more substances are formed with different properties because of this chemical reaction. Examples of chemical reactions are rust, combustion, and oxidation.
Answer:
When water freezes and turns into ice, it releases latent heat. Then, the ice that builds up on the plant will insulate it from the colder surrounding air temperatures. Because of this, some growers choose to spray their crop with water before the freeze occurs.
Explanation:
Answer:
the enthalpy change for this reaction is -57.7 kJ/mol
Explanation:
Given:
HB₂O₃ = -1272.8 kJ/mol
HCOCl₂ = -218.8 kJ/mol
HBCl₃ = -403.8 kJ/mol
HCO₂ = -393.5 kJ/mol
Those are all standard enthalpies
Question: Calculate the enthalpy change for this reaction, ΔHreaction = ?
The enthalpy of the reaction is calculated using the standard enthalpies of formation of both products and reagents. To understand better, the reaction is as follows
B₂O₃ + 3COCl₂ → 2BCl₃ + 3CO₂
Where the compounds on the left are the reactants and the compounds on the right are the products
ΔHreaction = ∑ΔHproducts - ∑ΔHreactants
Please be careful with the signs.