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Tamiku [17]
3 years ago
13

10. At point A, a runner is jogging 5 m/s. Forty seconds later, at point B

Physics
1 answer:
kondaur [170]3 years ago
5 0

Answer:

Deceleration of 0.075m/s²

Explanation:

Given parameters:

Initial velocity  = 5m/s

Time  = 40s

Final velocity  = 2m/s

Unknown:

The jogger's acceleration  = ?

Solution:

To solve this problem, we use;

         a  = \frac{v - u}{t}  

a is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

      a  = \frac{2 - 5}{40}   = - 0.075m/s²

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5 0
3 years ago
Read 2 more answers
Lila is a track and field athlete. She must complete four laps around a circular track. The track itself is a 400 meter track an
Aleonysh [2.5K]

Answer:

Her speed is 1.1 m/s, and her velocity is 0 m/s

Explanation:

Speed = Distance covered/Time

Given

Distance = 400m

Time = 6minutes = 6*60 = 360 secs

Substitute the given parameter into the formula;

Speed = 400/360

Speed = 1.1m/s

Since the track is a circular track, the displacement will be zero. She is only moving in a circular path (no direction)

Velocity = Displacement/Time

Velocity = 0/3600

Velocity = 0m/s

Hence her speed is 1.1 m/s, and her velocity is 0 m/s

6 0
3 years ago
Nvm i got the answer but <br> free points
faust18 [17]

Answer:

thank you 谢谢

Explanation:

8 0
3 years ago
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Nalah labels ten rats with the numbers 1 through 10. Then, she records how long it takes each rat to run through a maze. She fin
drek231 [11]

Answer:

we have to make another question we maxed it out again lol

Explanation:

5 0
3 years ago
A projectile is shot on level ground with a
erastova [34]

Answer:

time rising = 34 / 9.8 = 3.47 sec

total time in air = 2 * 3.47 sec = 6.94 sec

(time rising must equal time falling)

R = 17 m/s * 6.94 s = 118 m

Can also use range formula

R = v^2 sin (2 theta) / g

tan theta = 34 / 17 = 2

theta = 63.4 deg

2 theta = 126.9 deg

sin 126.9 = .8

v^2 = 17^2 + 34^2 = 1445 m^2/s^2

R = 1445 * .8 / 9.8 = 118 m    agreeing with answer found above

5 0
3 years ago
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