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xeze [42]
3 years ago
14

Please help it’s do soon

Physics
1 answer:
viktelen [127]3 years ago
8 0
When y’all are all over the place and I wanna is a time to come sit in my
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The Grinch is trying to push a 5000-kg sled up the side of Mount Crumpit (whose side make an angle of 60 degrees above the horiz
navik [9.2K]

Answer:

Explanation:

height lost h  = 300 sin60

= 259.8 m .

gravitational potential energy = mgh

= 5000 x 9.8 x 259.8

= 1273 x 10⁴ J

Kinetic energy

=  1/2 mv²

= .5 x 5000 x 60²

= 900 x 10⁴ J

there is loss of kinetic energy = 373 x 10⁴ J.

This loss in energy is due to kinetic friction that came into action when the sled slipped downwards.

The lost energy is converted into heat energy or thermal energy.

8 0
4 years ago
A block of mass 8 m can move without friction
nekit [7.7K]

Answer:

Let M1 = 8 kg and M2 = 34 kg

F = M a = (M1 + M2) a

F = M2 g     the net force accelerating the system

M2 g = (M1 + M2) a

a = M2 / (M1 + M2) g = 34 / (42) g = .81 g = 7.9 m/s^2

5 0
2 years ago
A ray of light traveling in water (n = 1.33) is incident at the flat surface of a block of glass (n = 1.60). If the incident ray
mel-nik [20]

Answer:

45.19^{\circ}

Explanation:

We are given that

n_1=1.33

n_2=1.6

\theta_1=58.6^{\circ}

We have to find the angle of refraction.

By Snell's law

n_1sin\theta_1=n_2sin\theta_2

Substitute the values

1.33sin58.6=1.6sin\theta_2

sin\theta_2=\frac{1.33sin58.6}{1.6}

sin\theta_2=0.7095

\theta_2=sin^{-1}(0.7095)=45.19^{\circ}

Hence, the angle mad by refracted ray in to the glass with normal=45.19^{\circ}

7 0
4 years ago
During aerobic activity, if your heart rate is lower than the lower limit, you are ___________________.
soldier1979 [14.2K]
Not pushing yourself hard enough is the answer since your heart rate doesn't even hit your lower minimum.
Pushing yourself to the limit is at your max heart rate.
Just at the right spot is at your max heart rate.
Pushing yourself too hard is above your max heart rate.
4 0
4 years ago
200 J of work is done when a force is applied to an object and the object moves 10 m to the right. How much Force was applied?
ArbitrLikvidat [17]

Answer:

 20N

Explanation:

Given parameters:

Work done  = 200J

Distance moved  = 10m

Unknown:

Amount of force applied  =?

Solution:

Work done is the force applied on a body to move it in the direction of the force.

      Work done  = force x distance

The unit of work done is in joules

Since the unknown is force, we make it the subject of the expression;

           Force  = \frac{Work done}{distance}

           Force  = \frac{200}{10}   =  20N

5 0
4 years ago
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