This is false. they flow west to east
The position vector can be
transcribed as:
A<span> = 6 i + y j
</span>
i <span>points in the x-direction and j points
in the y-direction.</span>
The magnitude of the
vector is its dot product with itself:
<span>|A|2 = A·A</span>
<span>102 = (6 i +
y j)•(6 i+ y j)
Note that i•j = 0, and i•i = j•j =
1 </span>
<span>100 = 36 + y2
</span>
<span>64 = y2</span>
<span>get the square root of 64 = 8</span>
<span>The vertical component of the vector is 8 cm.</span>
Answer:
![a=0.2*10^{-5}g](https://tex.z-dn.net/?f=a%3D0.2%2A10%5E%7B-5%7Dg)
Explanation:
From the question we are told that:
Mass ![M=180=>0.18kg](https://tex.z-dn.net/?f=M%3D180%3D%3E0.18kg)
Charge ![Q=18mC=18*10^-^3C](https://tex.z-dn.net/?f=Q%3D18mC%3D18%2A10%5E-%5E3C)
Velocity ![v=2.2m/s](https://tex.z-dn.net/?f=v%3D2.2m%2Fs)
Length of Wire ![L=8.6cm=>0.086](https://tex.z-dn.net/?f=L%3D8.6cm%3D%3E0.086)
Current ![I=30A](https://tex.z-dn.net/?f=I%3D30A)
Generally the equation for Magnetic Field of Wire B is mathematically given by
![B=\frac{\mu_0*I}{2\pi*l}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B%5Cmu_0%2AI%7D%7B2%5Cpi%2Al%7D)
![B=\frac{4*3.14*10^-^7*I}{2*3.14*8.6}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B4%2A3.14%2A10%5E-%5E7%2AI%7D%7B2%2A3.14%2A8.6%7D)
![B=6.978*10^{-5}T](https://tex.z-dn.net/?f=B%3D6.978%2A10%5E%7B-5%7DT)
Generally the equation for Force on the plane F is mathematically given by
![F=qvB](https://tex.z-dn.net/?f=F%3DqvB)
Therefore
![ma=qvB](https://tex.z-dn.net/?f=ma%3DqvB)
![a=\frac{qvB}{m}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7BqvB%7D%7Bm%7D)
![a=\frac{18*10^{-5}83.4*6.978*10^{-5}}{0.18kg}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B18%2A10%5E%7B-5%7D83.4%2A6.978%2A10%5E%7B-5%7D%7D%7B0.18kg%7D)
![a=2.37*10^{-5}](https://tex.z-dn.net/?f=a%3D2.37%2A10%5E%7B-5%7D)
Therefore in Terms of g's
![a=\frac{2.37*10^{-5}}{9.8}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B2.37%2A10%5E%7B-5%7D%7D%7B9.8%7D)
![a=0.2*10^{-5}g](https://tex.z-dn.net/?f=a%3D0.2%2A10%5E%7B-5%7Dg)
Answer:
The distance covered by puck A before collision is ![z = 8.56 \ m](https://tex.z-dn.net/?f=z%20%3D%208.56%20%5C%20m)
Explanation:
From the question we are told that
The label on the two hockey pucks is A and B
The distance between the two hockey pucks is D 18.0 m
The speed of puck A is ![v_A = 3.90 \ m/s](https://tex.z-dn.net/?f=v_A%20%3D%20%203.90%20%5C%20m%2Fs)
The speed of puck B is ![v_B = 4.30 \ m/s](https://tex.z-dn.net/?f=v_B%20%20%3D%20%204.30%20%5C%20m%2Fs)
The distance covered by puck A is mathematically represented as
![z = v_A * t](https://tex.z-dn.net/?f=z%20%3D%20%20v_A%20%2A%20t)
=> ![t = \frac{z}{v_A}](https://tex.z-dn.net/?f=t%20%20%3D%20%20%5Cfrac%7Bz%7D%7Bv_A%7D)
The distance covered by puck B is mathematically represented as
![18 - z = v_B * t](https://tex.z-dn.net/?f=18%20-%20z%20%3D%20%20v_B%20%20%2A%20t)
=> ![t = \frac{18 - z}{v_B}](https://tex.z-dn.net/?f=t%20%20%3D%20%5Cfrac%7B18%20-%20z%7D%7Bv_B%7D)
Since the time take before collision is the same
![\frac{18 - z}{V_B} = \frac{z}{v_A}](https://tex.z-dn.net/?f=%5Cfrac%7B18%20-%20z%7D%7BV_B%7D%20%20%3D%20%20%5Cfrac%7Bz%7D%7Bv_A%7D)
substituting values
![\frac{18 -z }{4.3} = \frac{z}{3.90}](https://tex.z-dn.net/?f=%5Cfrac%7B18%20-z%20%7D%7B4.3%7D%20%20%3D%20%5Cfrac%7Bz%7D%7B3.90%7D)
=> ![70.2 - 3.90 z = 4.3 z](https://tex.z-dn.net/?f=70.2%20-%203.90%20z%20%20%20%3D%204.3%20z)
=> ![z = 8.56 \ m](https://tex.z-dn.net/?f=z%20%3D%208.56%20%5C%20m)