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Alja [10]
3 years ago
8

The thermal conductivity of a sheet of rigid, extruded insulation is reported to be k=0.029 W/m.K. The measured temperature diff

erence across a 25-mm-thick sheet of the material is LaTeX: T_1-T_2\:=\:12°CT 1 − T 2 = 12 ° C . a) What is the heat flux (in W/m2) through a 3m by 3m sheet of the insulation?
Physics
1 answer:
klasskru [66]3 years ago
3 0

Answer:

flux=13.92W/m^2

Explanation:

The heat transfer by conduction consists in the transport of energy through particles that are together, that is to say by means of solids, Newton developed an equation that allows to know the heat transported in a flat plate knowing the cross sectional area A, Thickness L, conductivity  K  and a temperature difference between the internal and external surface.

Q=KA(t2-t1)/L

To know the heat flux we simply divide both sides of the equation by the area.

Flux=K(t2-t1)/L

where

K=0.029w/mk

L=25mm=0.025m

t2-t1=12 ° C

solving

Flux=(0.029)(12)/(0.025)

flux=13.92W/m^2

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2.66N

Explanation:

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Answer:

Find answers below.

Explanation:

Given the following data;

Voltage = 220V

Current = 15 A

a. To find the power;

Power = current * voltage

Power = 15 * 220

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b. To find the energy;

Time = 8 hours = 60 * 60 * 8 = 28800 seconds

Energy = power * time

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Energy = 26400

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8 0
2 years ago
A worker pushes a box across the floor to the right at a constant speed with a force of 25N. What
icang [17]

Answer:

Friction between the box and the floor is 25N to the left

Explanation:

There are two forces acting on the box along the horizontal direction:

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- The force of friction, F_f, acting in the opposite direction (backward)

So the net force acting on the box is

F_{net}=F-F_f

According to Newton's second law of motion, the net force on an object is equal to the product between its mass (m) and its acceleration (a), so we can write:

F_{net}=ma

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F-F_f = ma

However, in this case the box is moving at constant speed; this means that its acceleration is zero:

a=0

Therefore we have:

F-F_f=0

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F_f=F

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This means that the force of friction is also 25 N:

F_f=F=25 N

6 0
3 years ago
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Light of wavelength 530.00 nm is incident normally on a diffraction grating, and the first‑order maximum is observed to be 33.0∘
GarryVolchara [31]

Answer:

1028 slits/mm

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We are given that

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1nm=10^{-9} m

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We have to find the number of slits per mm are marked on the grating.

We know that

dsin\theta=n\lambda

Using the formula

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d=\frac{530\times 10^{-9}}{sin33^{\circ}}

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Number of slits=\frac{1}{0.0009731}/mm

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Answer: The control group is the part where you see what happens when you change a variable you want to study/examine. Basically, you need the control group because you need something to see what happens when you change something.

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