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k0ka [10]
2 years ago
6

Bob spent $64 for two shirts, including tax. The difference between the costs of the shirts was $16. Write two equations that yo

u will use to solve the system
Mathematics
2 answers:
NemiM [27]2 years ago
8 0

Answer:

The cost of the shirts are $40 and $24

Step-by-step explanation:

Let

x ----> the cost of one shirt

y ----> the cost of the other shirt

we know that

x+y=64 ----> equation A

I assume that the cost x is greater than the cost y

so

x-y=16 ----> x=y+16 ---> equation B

solve the system by substitution

substitute equation B in equation A

y+16+y=64

solve for y

2y=64-16

2y=48

y=\$24

Find the value of x

x=y+16 ---->  x=24+16=\$40

therefore

The cost of the shirts are $40 and $24

djyliett [7]2 years ago
5 0

x+y=64 and x-y=16 can be used to solve the system.

Step-by-step explanation:

Let,

x,y be the two shirts.

According to given statement;

Bob spent $64 on both shirts;

x+y=64    Eqn 1

The difference between the costs of the shirts was $16 means subtraction;

x-y=16      Eqn 2

x+y=64 and x-y=16 can be used to solve the system.

Keywords: linear equation, addition

Learn more about linear equations at:

  • brainly.com/question/902892
  • brainly.com/question/909731

#LearnwithBrainly

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Answer:

A, d and e

Step-by-step explanation:

So take the numbers a multiply them by nine. if they are more than 117, then they are correct, but with D 9x13 is equal to 117 so it is part of the solution set.

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<h3>What is volume?</h3>

Volume is defined as the space occupied by any object in the three-Dimensions. All three parameters are required for the volume like length, width and height of the cube and for the cone it will be radius and height.

It is given that:-

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Answer:

  a. f(0) = 1

  b. DNE (does not exist)

  c. DNE

  d. lim = 3

Step-by-step explanation:

The function exists at a point if it is defined there. The function is defined anywhere on the solid line and at solid dots. It is not defined at open circles. So, the function is defined everywhere except (2, 3), which has an open circle.

The open circle at (0, 4) prevents the function from being doubly-defined at x=0, since it is already defined to be 1 at x=0.

This discussion tells you ...

  f(0) = 1

 f(2) does not exist. There is a "hole" in the function definition there.

__

The function has a limit at a point if approaching from the left and approaching from the right have you approaching that same point.

Consider the point (1, 2). The graph is a solid line through that point. Approaching from values less than x=1, we get to the same point (1, 2) as when we approach from values greater than x=1.

Similarly, consider the point (2, 3). Approaching from values of x less than 2, we get to the same point (2, 3) as when we approach from x-values greater than 2. The limit at x=2 is 3. The only difference from the previous case is that the function is not actually defined to be that value there.

__

Now consider what happens at x=0. When we approach from the left, we approach the point (0, 4). When we approach from the right, we approach the point (0, 1). These are different points. Because they are different coming from the left and from the right, we say "the limit as x→0 does not exist."

__

In summary, ...

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_____

<em>Additional comment</em>

The significance of the function not being defined at a point where the limit exists, (2, 3), is that <em>the function is not continuous there</em>. This kind of discontinuity is called "removable", because we could make the function continuous at x=2 by defining f(2) = 3 (that is, "filling the hole").

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