Answer:
Triangles ABE and CDE are congruent by AAS.
Step-by-step explanation:
AB ≅ DC (Opposite sides of a parallelogram are congruent.
m < AEB = m < DEC (Vertical angles).
m < ABE = m < EDC ( Alternate Interior angles).
So triangles ABE and CDE are congruent by AAS.
Try this suggested solution, note, 'D' means the region bounded by the triangle according to the condition. It consists of 6 steps.
Answers are underlined with red colour.
<span> first, write the equation of the parabola in the required form: </span>
<span>(y - k) = a·(x - h)² </span>
<span>Here, (h, k) is given as (-1, -16). </span>
<span>So you have: </span>
<span>(y + 16) = a · (x + 1)² </span>
<span>Unfortunately, a is not given. However, you do know one additional point on the parabola: (0, -15): </span>
<span>-15 + 16 = a· (0 + 1)² </span>
<span>.·. a = 1 </span>
<span>.·. the equation of the parabola in vertex form is </span>
<span>y + 16 = (x + 1)² </span>
<span>The x-intercepts are the values of x that make y = 0. So, let y = 0: </span>
<span>0 + 16 = (x + 1)² </span>
<span>16 = (x + 1)² </span>
<span>We are trying to solve for x, so take the square root of both sides - but be CAREFUL! </span>
<span>± 4 = x + 1 ...... remember both the positive and negative roots of 16...... </span>
<span>Solving for x: </span>
<span>x = -1 + 4, x = -1 - 4 </span>
<span>x = 3, x = -5. </span>
<span>Or, if you prefer, (3, 0), (-5, 0). </span>
Each time you are subtracting 1/9 to get the next term
For example, going from term 2 to term 3 is a difference of -1/9
(1 8/9) - (1/9) = 1 7/9
which is why the answer is choice A
