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lisabon 2012 [21]
3 years ago
13

If one serving of a packaged frozen dinner contains 5.2 grams of saturated fat and the maximum recommended daily intake of satur

ated fat is 20 grams, what percent daily value (%DV) for saturated fat does one package of this food provide? Answer to 1 decimal place.
Chemistry
1 answer:
den301095 [7]3 years ago
7 0

Answer:

The percentage of the daily value for saturated fat provided by one package of this food is 26.0%

Explanation:

It has been given from the preceding statement that one package of the dinner provides 5.2g out of the 20 grams recommended for daily need. This is 5.2/20 x 100 given 26.0% of the daily neded value will be provided by a plate or package of the dinner.

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Determine the equilibrium constant, Keq, at 25°C for the reaction
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Explanation:

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2Br^- (aq) + I_2(s)  Br_2(l) + 2I^- (aq)

E^ocell=oxidation potential of anode + reduction potential of cathode\\

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deltaG=-RTlnK_e_q\\delta=-nFE^o cell\\=>nFE^o cell=RTlnK_e_q\\lnK_e_q=\frac{nF}{RT} E^o cell

The value of Eo cell is:

Br- undergoes oxidation and I2 undergoes reduction.

Reduction takes place at cathode.

Oxidation takes place at anode.

Hence,

E^ocell= (-1.07+0.53)V\\=-0.54V

F=96485 C/mol

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R=8.314 J.K-1.mol-1

T=298K

Substitute all these values in the above formula:

ln K_e_q=\frac{2mol* 96485 C/mol}{8.314 J.K^-^1.mol^-^1x298K} \\\\lnK_e_q=77.8\\K_e_q=e^7^7^.^8\\=>K_e_q=6.13x10^3^3

Answer:

Keq=6.13x10^33

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Answer:

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Hope this helped!
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Ana drives at a speed of 175m/s. she recorded a distance of 2km. Find the time.
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When studying atoms, scientists can ignore the
vekshin1

When studying atoms, scientists can ignore <u>the Gravitational</u> force between charged particles that make up  the atoms because it is many millions of times smaller than other forces in the atom.

Explanation:

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