Iodine electron configuration is:
1S^2 2S^2 2P^6 3S^2 3P^6 4S^2 3d^10 4P^6 5S^2 4d^10 5P^5
when Krypton is the noble gas in the row above iodine in the periodic table,
we can change 1S^2 2S^2 2P^6 3S^2 3P^6 4S^2 3d^10 4P^6 by the symbol
[Kr] of Krypton.
So we can write the electron configuration of Iodine:
[Kr] 5S^2 4d^10 5P^5
The final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L.
<h3>How to calculate volume?</h3>
The volume of a given gas can be calculated using the Charles law equation as follows:
V1/T1 = V2/T2
Where;
- V1 = initial volume
- V2 = final volume
- T1 = initial temperature
- T2 = final temperature
- V1 = 2L
- V2 = ?
- T1 = -25°C + 273 = 248K
- T2 = 273K
2/248 = V2/273
273 × 2 = 248V2
546 = 248V2
V2 = 546/248
V2 = 2.2L
Therefore, the final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L
Learn more about volume at: brainly.com/question/11464844
Answer:
B-Sucrose molecules are too large to conduct electricity in once dissolved in water.
D-Salts, like NaCL, have ionic bonds and are considered to be electrolytes:when dissolved in water, salts dissociate and form ions.
Explanation:
Answer:
m(H₂O) = 97,2 g.n(H₂O) = m(H₂O) ÷ M(H₂O).n(H₂O) = 97,2 g ÷ 18
Explanation:
The correct answer is letter a. distillation of a mixture. “Gasoline boils at a relatively low temperature (about 150°C). The kerosene is removed at around 200°C, followed by diesel oil at 300°C and fuel oil ataround 370°C," It is the process of DISTILLATION OF A MIXTURE.Here is the question.
<span>
What topic is the teacher most likely talking about?
a. distillation of a mixture
b. filtration of a pure substance
c.evaporation of a mixture
d. sorting of a pure substance</span>
